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Shell Programming and Scripting
wget output file names
Post 302672689 by alister on Monday 16th of July 2012 08:18:35 PM
07-16-2012
Quote:
Alternatively, you can stick with your original approach, which generates the undesirable filenames, and rename the files afterwards (perhaps with the rename utility).
In my opinion, scott's solution is preferable. Keep it simple.
Regards,
Alister
Last edited by alister; 07-16-2012 at 09:25 PM..
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LEARN ABOUT LINUX
prename
RENAME(1) Perl Programmers Reference Guide RENAME(1) NAME
rename - renames multiple files SYNOPSIS
rename [ -v ] [ -n ] [ -f ] perlexpr [ files ] DESCRIPTION
"rename" renames the filenames supplied according to the rule specified as the first argument. The perlexpr argument is a Perl expression which is expected to modify the $_ string in Perl for at least some of the filenames specified. If a given filename is not modified by the expression, it will not be renamed. If no filenames are given on the command line, filenames will be read via standard input. For example, to rename all files matching "*.bak" to strip the extension, you might say rename 's/.bak$//' *.bak To translate uppercase names to lower, you'd use rename 'y/A-Z/a-z/' * OPTIONS
-v, --verbose Verbose: print names of files successfully renamed. -n, --no-act No Action: show what files would have been renamed. -f, --force Force: overwrite existing files. ENVIRONMENT
No environment variables are used. AUTHOR
Larry Wall SEE ALSO
mv(1), perl(1) DIAGNOSTICS
If you give an invalid Perl expression you'll get a syntax error. BUGS
The original "rename" did not check for the existence of target filenames, so had to be used with care. I hope I've fixed that (Robin Barker). perl v5.12.4 2011-08-10 RENAME(1)