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Top Forums Shell Programming and Scripting How to run a shell script on a remote host using ftp Post 302672415 by mrskittles99 on Monday 16th of July 2012 11:21:12 AM
Old 07-16-2012
Quote:
Originally Posted by jim mcnamara
Is telnet running on the remote host?
telnet is running, i just tried the following telnet script on it, it worked but there is code in my ksh script after the telnet commands, and that code doesn't execute, as if the script is unable to get out of telnet:

Code:
 
#!usr/bin/ksh
 
(sleep 2
echo user
sleep 1
echo pass
sleep 2
echo "/path/to/script.ksh"
sleep 1
echo "exit") | telnet host1
#program freezes here i think
 
#more code to execute

---------- Post updated at 11:21 AM ---------- Previous update was at 10:42 AM ----------

Quote:
Originally Posted by joeyg
Perhaps something with
scheduled cron task
the task checks for the existence of a file
(this could be ftp'ed to the remote system)
then a script is executed
I don't have experience with cron but doesn't that just run a script at certain time intervals? I want to run the script whenever I prompt it to run.

Last edited by mrskittles99; 07-16-2012 at 11:48 AM..
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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