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Top Forums Shell Programming and Scripting Issue with output redirection Post 302672127 by pmonika on Monday 16th of July 2012 02:57:55 AM
Old 07-16-2012
Issue with output redirection

Hi,

I am using AIX server. I have a korn shell script where in I am redirecting a line to a file in a while loop:


Code:
while read line
do
     outputline=$line;
     echo $outputline >> "./temp/exec_list_"$ETL_JOB_RUN"_temp"
done < ./temp/exec_list_$ETL_JOB_RUN

Sometimes, when the CPU usage goes upto 99%, the command "echo $outputline >> "./temp/exec_list_"$ETL_JOB_RUN"_temp"" does not work and skips to the next step. I think, the writer process is slower than the reader process or we'll have to increase the pipe size.

Any suggestions how this can be achieved?


Moderator's Comments:
Mod Comment Please use code tags next time for your code and data.

Last edited by zaxxon; 07-16-2012 at 10:30 AM.. Reason: code tags, see PM
 

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EVAL(3) 								 1								   EVAL(3)

eval - Evaluate a string as PHP code

SYNOPSIS
mixed eval (string $code) DESCRIPTION
Evaluates the given $code as PHP. Caution The eval(3) language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged. If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user provided data into it without properly validating it beforehand. PARAMETERS
o $code - Valid PHP code to be evaluated. The code mustn't be wrapped in opening and closing PHP tags, i.e. 'echo "Hi!";' must be passed instead of '<? echo "Hi!"; >'. It is still possible to leave and reenter PHP mode though using the appropriate PHP tags, e.g. 'echo "In PHP mode!"; ?>In HTML mode!<? echo "Back in PHP mode!";'. Apart from that the passed code must be valid PHP. This includes that all statements must be properly terminated using a semicolon. 'echo "Hi!"' for example will cause a parse error, whereas 'echo "Hi!";' will work. A return statement will immediately terminate the evaluation of the code. The code will be exe- cuted in the scope of the code calling eval(3). Thus any variables defined or changed in the eval(3) call will remain visible after it terminates. RETURN VALUES
eval(3) returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. If there is a parse error in the evaluated code, eval(3) returns FALSE and execution of the following code continues normally. It is not possible to catch a parse error in eval(3) using set_error_handler(3). EXAMPLES
Example #1 eval(3) example - simple text merge <?php $string = 'cup'; $name = 'coffee'; $str = 'This is a $string with my $name in it.'; echo $str. " "; eval("$str = "$str";"); echo $str. " "; ?> The above example will output: This is a $string with my $name in it. This is a cup with my coffee in it. NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. Tip As with anything that outputs its result directly to the browser, the output-control functions can be used to capture the output of this function, and save it in a string (for example). Note In case of a fatal error in the evaluated code, the whole script exits. SEE ALSO
call_user_func(3). PHP Documentation Group EVAL(3)
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