I have about 300 files which has the function getDBBackend().
How to write a program to change the empty function from the old format to the new format?
Old empty function format are either:
function getDBBackend()
{
// Not available
} // getDBBackend
or:
function... (0 Replies)
Hello,
Can you tell me how can I change this format by awk
Input
0.2057422D-01
0.2463722D-01
-0.1068047D-02
Output
0.02057422
0.02463722
-0.001068047
Thanks
wan (8 Replies)
Hi,
i have a file input.txt
Continent North America
Country USA Capital Washington D.C.
Country Canada Capital Ottawa
Continent South America
Country Argentina Capital Buenos Aires
Country Brazil Capital Brasília
Coutry Colombia Capital Bogotá
and i want to get an output.txt
... (3 Replies)
I have below date format in a CSV file. (dd/mm/yyyy)
Ex Input:
9/8/2013
Need to convert it into below format (yyyymmdd ) and redirect to new file.
Ex Output:
20130809
How do I use awk here to change the format and if leading 0 (zero) is not then add it.
Please help. Thanks. (8 Replies)
Basically I am trying to run a standard output of IP address with a port number into another command but I need to change it from.
74.125.224.194.80 into 74.125.224.194:80
One command wants a period before the port the subsequent one wants a colon.
So is there anyway I can feed... (3 Replies)
Greetings!
I need a quick way to change the format in a table of data
Here is an example of the input:
10 72 Value=177 VDB=0.0245 Value4=0,0,171,0
10 274 Value=238 VDB=0.0433 Value4=29,0,205,0
10 312 Value=222 VDB=0.0384 Value4=8,0,190,19
10 540 Value=405 VDB=0.0391 Value4=13,30,153,195... (3 Replies)
I have a csv file formatted like this:
2014-08-21 18:06:26,A,B,12345,123,C,1232,26/08/14 18:07and I'm trying to change it to MM/DD/YYYY HH:MM for both occurances.
I have got this:
awk -F, 'NR <=1 {print;next}{"date +%d/%m/%Y\" \"%H:%m -d\""$1 "\""| getline dte;$1=dte}1' OFS="," test.csvThis... (6 Replies)
Hi,
I have a file where I need to change the date format on the nth field from DD-MM-YYYY to YYYY-MM-DD so I can accurately sort the record by dates
From regex - Use sed or awk to fix date format - Stack Overflow, I found an example using nawk.
Test run as below:
$: cat xyz.txt
A ... (2 Replies)
Discussion started by: newbie_01
2 Replies
LEARN ABOUT LINUX
dscextract
DSCEXTRACT(1) General Commands Manual DSCEXTRACT(1)NAME
dscextract - extract a single file from a Debian source package
SYNOPSIS
dscextract [options] dscfile file
DESCRIPTION
dscextract reads a single file from a Debian source package. The idea is to only look into .diff.gz files (source format 1.0) or
.debian.tar.gz/bz2 files (source format 3.0) where possible, hence avoiding to unpack large tarballs. It is most useful for files in the
debian/ subdirectory.
file is relative to the first level directory contained in the package, i.e. with the first component stripped.
OPTIONS -f "Fast" mode. For source format 1.0, avoid to fall back scanning the .orig.tar.gz file if file was not found in the .diff.gz. (For
3.0 packages, it is assumed that debian/* are exactly the contents of debian.tar.gz/bz2.)
EXIT STATUS
0 file was extracted.
1 file was not found in the source package.
2 An error occurred, like dscfile was not found.
EXAMPLE
dscextract dds_2.1.1+ddd105-2.dsc debian/watch || test $? = 1
AUTHOR
dscextract was written by Christoph Berg <myon@debian.org>.
DEBIAN Debian Utilities DSCEXTRACT(1)