I have about 300 files which has the function getDBBackend().
How to write a program to change the empty function from the old format to the new format?
Old empty function format are either:
function getDBBackend()
{
// Not available
} // getDBBackend
or:
function... (0 Replies)
Hello,
Can you tell me how can I change this format by awk
Input
0.2057422D-01
0.2463722D-01
-0.1068047D-02
Output
0.02057422
0.02463722
-0.001068047
Thanks
wan (8 Replies)
Hi,
i have a file input.txt
Continent North America
Country USA Capital Washington D.C.
Country Canada Capital Ottawa
Continent South America
Country Argentina Capital Buenos Aires
Country Brazil Capital Brasília
Coutry Colombia Capital Bogotá
and i want to get an output.txt
... (3 Replies)
I have below date format in a CSV file. (dd/mm/yyyy)
Ex Input:
9/8/2013
Need to convert it into below format (yyyymmdd ) and redirect to new file.
Ex Output:
20130809
How do I use awk here to change the format and if leading 0 (zero) is not then add it.
Please help. Thanks. (8 Replies)
Basically I am trying to run a standard output of IP address with a port number into another command but I need to change it from.
74.125.224.194.80 into 74.125.224.194:80
One command wants a period before the port the subsequent one wants a colon.
So is there anyway I can feed... (3 Replies)
Greetings!
I need a quick way to change the format in a table of data
Here is an example of the input:
10 72 Value=177 VDB=0.0245 Value4=0,0,171,0
10 274 Value=238 VDB=0.0433 Value4=29,0,205,0
10 312 Value=222 VDB=0.0384 Value4=8,0,190,19
10 540 Value=405 VDB=0.0391 Value4=13,30,153,195... (3 Replies)
I have a csv file formatted like this:
2014-08-21 18:06:26,A,B,12345,123,C,1232,26/08/14 18:07and I'm trying to change it to MM/DD/YYYY HH:MM for both occurances.
I have got this:
awk -F, 'NR <=1 {print;next}{"date +%d/%m/%Y\" \"%H:%m -d\""$1 "\""| getline dte;$1=dte}1' OFS="," test.csvThis... (6 Replies)
Hi,
I have a file where I need to change the date format on the nth field from DD-MM-YYYY to YYYY-MM-DD so I can accurately sort the record by dates
From regex - Use sed or awk to fix date format - Stack Overflow, I found an example using nawk.
Test run as below:
$: cat xyz.txt
A ... (2 Replies)
Discussion started by: newbie_01
2 Replies
LEARN ABOUT DEBIAN
cpan::perl::releases
CPAN::Perl::Releases(3pm) User Contributed Perl Documentation CPAN::Perl::Releases(3pm)NAME
CPAN::Perl::Releases - Mapping Perl releases on CPAN to the location of the tarballs
VERSION
version 0.60
SYNOPSIS
use CPAN::Perl::Releases qw[perl_tarballs];
my $perl = '5.14.0';
my $hashref = perl_tarballs( $perl );
print "Location: ", $_, "
" for values %{ $hashref };
DESCRIPTION
CPAN::Perl::Releases is a module that contains the mappings of all "perl" releases that have been uploaded to CPAN to the "authors/id/"
path that the tarballs reside in.
This is static data, but newer versions of this module will be made available as new releases of "perl" are uploaded to CPAN.
FUNCTIONS
"perl_tarballs"
Takes one parameter, a "perl" version to search for. Returns an hashref on success or "undef" otherwise.
The returned hashref will have a key/value for each type of tarball. A key of "tar.gz" indicates the location of a gzipped tar file and
"tar.bz2" of a bzip2'd tar file. The values will be the relative path under "authors/id/" on CPAN where the indicated tarball will be
located.
perl_tarballs( '5.14.0' );
Returns a hashref like:
{
"tar.bz2" => "J/JE/JESSE/perl-5.14.0.tar.bz2",
"tar.gz" => "J/JE/JESSE/perl-5.14.0.tar.gz"
}
Not all "perl" releases had "tar.bz2", but only a "tar.gz".
SEE ALSO
<http://www.cpan.org/src/5.0/>
<http://search.cpan.org/faq.html#Is_there_a_API?>
AUTHOR
Chris Williams <chris@bingosnet.co.uk>
COPYRIGHT AND LICENSE
This software is copyright (c) 2012 by Chris Williams.
This is free software; you can redistribute it and/or modify it under the same terms as the Perl 5 programming language system itself.
perl v5.14.2 2012-06-20 CPAN::Perl::Releases(3pm)