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Full Discussion: Initialization error
Top Forums Shell Programming and Scripting Initialization error Post 302670367 by ygemici on Thursday 12th of July 2012 03:33:26 AM
Old 07-12-2012
Quote:
Originally Posted by scriptor
full script is

${parameter:=word}

echo $parameter

and below is the o/p

word: not found.
word
** ${parameter:=word}
### when you first execute that and if parameter is null or not set then ksh genaretes an error but assigns to "word" to parameter value..
Code:
# ${parameter:=word}
ksh: word:  not found.
# echo $parameter
word

### after that the first execute that command , then other executes ksh also genarete errors because of ksh executes for first argument ( ${parameter,,,,} ) so now parameter value's is "word",and returns the "word not found" error and then quit the executing process(shell internals)..

this same to that ( try this )
Code:
# word
ksh: word:  not found.



** ${parameter:=$word}
### when you execute this , ksh runs successfully and because of parameter and word value is null already.. (so any change and no error )
Code:
# ${parameter:=$word}
#



### first try below command , ksh returns same results because of ksh wants to execute word value and then returns the error normally but
parameter value assings to "10", because paramater value is NULL for first try or when parameter is null
Code:
# word=10
# ${parameter:=$word}
ksh: 10:  not found.
# echo $parameter
10

### other executes after than first , now parameter value was 10
and ksh tries to execute parameter value so "10" executed and then so ksh gives the error and quit from subsitution process in shell internal.
Code:
# ${parameter:=$word}
ksh: 10:  not found.

** with echo
ksh and bash does not generate any errors and echoes the assigment results..
Code:
# echo ${parameter:=$word}
10

and the other one
Code:
# parameter=""
# word=20
# echo ${parameter:=$word}
20


regards
ygemici
This User Gave Thanks to ygemici For This Post:
 

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