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Top Forums Shell Programming and Scripting awk get search pattern from a file. Post 302666297 by balajesuri on Wednesday 4th of July 2012 05:48:27 AM
Old 07-04-2012
Quote:
Originally Posted by togotutor
Query --> I want to search for a string in a file and print next 15 lines below the matched string.
With whatever little awk knowledge I have, this is what I could assimilate into a solution:
Code:
awk '/pattern/ {c=0; f=1; print; next} f==1 && c<=15 {print; c++} c==15 {exit}' inputfile

After a bit of googling, I found a solution in this link.
Code:
awk '/pattern/{c=15;{print}next}c-->0' inputfile


Last edited by balajesuri; 07-04-2012 at 06:57 AM..
 

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IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
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