Hi,
Is is possible to get the value using shell script?
x=1
y1 = 10
y2 = 15
y3 = 7
echo $y$x is giving y1 (variable name)
but I need the value of y1 (i.e. 10 dynamically)
Is there any solution?
if so, please mail me at kkodava@maxis.com.my
... (2 Replies)
Hi,
I do have a file and the contents are as follws:
10
20
30
40
50
Now I want to store those values into an array. How can be done this ?? (3 Replies)
I know there are caveats about using read in pipelines because read is treated by a subshell. I know this but I can't think of any way to accomplish this regardless, I'm still a rookie.
I hope somebody will be able to interpret what it is that I'm trying to accomplish and correct me.
... (2 Replies)
Hi all.
Well, I have the next code:
I need to make an array with the values I have in the bucle, but just don't get it...
Question is, how can I store in an array that values, and how can I display them with echo? (8 Replies)
Hi
I want to write a script which store all the parameters passed to the script into an array.
Once it is stored I want scan through the array and and delete those files for last month present inside the directory. The files in directory is appneded with YYYY_MM_DD.
I want to know how can I... (3 Replies)
Hello Guys,
I am trying to store output of command to an array and then want to print, but it showing an error that "bad substitution". I am not getting why it's happening.
Can anyone help me?
#!/usr/bin/sh
hr=0
min=0
i=1
last $1 | grep -w `date "+%b"` | grep -v '\(0:.*\)' | grep -vw sshd... (8 Replies)
Dear All,
I have been trying to do a simple task of extracting 2 fields from the file (3 rows) and store it in an array variable. I tried with:
#! /bin/bash
ch=`cut -f10 tmp.txt`
counter=0
for p in $pid
do
c=${ch}
echo "$c ..$counter"
counter=$((counter+1))... (2 Replies)
I am reading a value from a file and want to store the value in a dynamic array as i don't know the number of occurrences of the value in that file.
How can i do that and then later fetch that value from array (25 Replies)
I have awk command :
awk -F ' ' '{ print $NF }' log filename
And it gives the output as below:
06:00:00
parameters:
SDS
(2)
no
no
no
no
doc=4000000000).
information: (6 Replies)