INPUT FILE:
Then repeats (the field after 10 on the the B 0: line increments from 00 to 06) with new times and new data (except 10 will always be in the same field on the B 0: line).
What I would like the output to be (sometimes data is missing so checks will have to be done)
I would like to find the B 0: line that contains 10 00 and then print the line above it if it contains Date: then if that checks out print the B 0: line that contains 10 00. Right after these 2 lines are printed I would like to find the B 0: line that contains 10 04 then print the line above it if contains Date:, then print the B 0: line that contains 10 04 that was just found, then print the line right below the B 0: line that contains 10 04 if it contains B 120:. Right after these 2 lines are printed I would like to find the B 0: line that contains 10 06 then print the line above it if contains Date:, then print the B 0: line that contains 10 06 that was just found, then print the line right below the B 0: line that contains 10 06 if it contains B 120:. I would like this done for the entire file (going to the next set of data). Sorry this is fairly confusing.
Below is the output I would like.
If the input file was larger the next set of data might look like this:
FYI: I am using solaris 10 and don't have any GNU products installed. I've tried using egrep without success.....I'm thinking awk would be better...but I'm not sure. If you know how to solve this problem...your help would be appreciated.
Last edited by Scrutinizer; 06-30-2012 at 07:45 PM..
Reason: code tags and cleaned spurious formatting
I'm trying to write a script which prints out the users who are loged in.
Printing the output of the "users" command isn't the problem. What I want is to filter out my own username.
users | grep -v (username)
does not work because the whole line in which username exists is suppressed.
If... (5 Replies)
I want to remove everything from a file but the word following the search word.
Example:
crap crap crap crap SearchWord WordToKeep crap crap crap
How would I do this with say awk or grep?
Thank you! (4 Replies)
Hi how can I filter the text using this one.
SAMPLE
servervmpool -listall|tail -11
================================================================================
pool number: 112
pool name: Net-Ora-1wk
description: Net-Ora-1wk
max partially full: 0... (12 Replies)
Still new to bash. Using debian lenny 5, bash version 3.2.39. I'm working on three scripts. I need help completing them.
One script that inputs a plain text file, echo then chop it up into separate whitespace-delimited strings as an output. Not sure how to do this...
for example, the... (4 Replies)
I have to grep a pattern. scenario is like :-
Suppose "/etc/sec/one" is a string, i need to check if this string contains "one" using any utility
something like
if /etc/sec/one | grep ; then
Thanks in advance
Renjesh Raju (3 Replies)
I have a log file that contains several reports with following format.
<Start of delimiter> Report1 header
Report1 header continue
Report1 header continue
Record1 header
Record1 header continue
Record1 header continue
field1 field2 field3 field4
------... (1 Reply)
Hi!!
I have a bit of a task here and filtering/scripting not my strongest. I have to collect info of approx 1100 hdiskpower.so i have appended all the hdisk into a text file and i need it to run the command lscfg -vl to confirm if the drive is symmetrix. here's what i have so far
at... (3 Replies)
Hello,
Is there a way to filerter data from a text file as shown below to a Column
e.g.
hostname nfsmount as two separate column. Currently I could get hostname and the mount is appearing below.. using this script
#! /bin/bash
for i in `cat fqdn.txt`
do
echo "$i ............ " >>... (3 Replies)
I need to filter a file that is composed like that:
>Cluster 0
0 292nt, >last294258;size=1;... *
>Cluster 1
0 292nt, >last111510;size=1;... *
1 290nt, >last136280;size=1;... at -/98.62%
2 292nt, >last217336;size=1;... at +/99.66%
3 292nt, >last280937;size=1;... at -/99.32%
>Cluster 2... (6 Replies)
Discussion started by: pedro88
6 Replies
LEARN ABOUT CENTOS
dm_date
DM_DATE(1) User Contributed Perl Documentation DM_DATE(1)NAME
dm_date - print out the system date and time
SYNOPSIS
This performs the same operation as the unix 'date' command, but using the Date::Manip module.
dm_date [OPTION]... [+FORMAT]
DESCRIPTION
This displays information about the current system time, or some other time. Options are:
-h, --help
Print online help.
-d STRING, --date=STRING
Display time described by STRING. STRING can be any string which can be parsed by Date::Manip. Please refer to the Date::Manip::Date
documentation for details.
-f DATEFILE, --file=DATEFILE
This reads each line in DATEFILE, and extracts a date from it and prints out the information.
Blank lines and lines starting with a pound (#) are ignored. Lines not containing a valid date are also ignored.
-r FILE, --reference=FILE
Displays the last modification time of FILE.
-R, --rfc-2822
Displayc the date and time in RFC 2822 format.
Example: Mon, 07 Aug 2006 12:34:56 -0600
-u, --utc, --universal
Converts the date to UT (GMT) and prints out the information.
Only one of -d, -f, or -r should be included. If more than one is included, the first one from the list (-d, -f, -r) is used and any other
is ignored.
The format string starts with a plus (+) and contains any of the format directives described in Date::Manip::Date.
KNOWN BUGS
None known.
BUGS AND QUESTIONS
Please refer to the Date::Manip::Problems documentation for information on submitting bug reports or questions to the author.
SEE ALSO
Date::Manip::Date
LICENSE
This script is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
AUTHOR
Sullivan Beck (sbeck@cpan.org)
perl v5.16.3 2014-06-09 DM_DATE(1)