Need a quick and dirty solution Post: 302664319

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Top Forums Shell Programming and Scripting Need a quick and dirty solution Post 302664319 by drl on Friday 29th of June 2012 10:15:57 AM

06-29-2012

Registered User

Hi, elixir_sinar.

Quote:

Originally Posted by elixir_sinari

Is there any problem in this solution, alister?

Code:

awk -F"[ v.]" '$3+0==vleft[$1]+0 && $4"">vright[$1]"" {vright[$1]=$4} $3+0>vleft[$1]+0 {vleft[$1]=$3;vright[$1]=$4} END {for(i in vleft) print i" v"vleft[i]"."vright[i]}' inputfile

Well, let us try it:

Code:

#!/usr/bin/env bash

# @(#) user2	Demonstrate proposed awk solution for "version" strings.

pe() { for _i;do printf "%s" "$_i";done; printf "\n"; }
pl() { pe;pe "-----" ;pe "$*"; }
db() { ( printf " db, ";for _i;do printf "%s" "$_i";done;printf "\n" ) >&2 ; }
db() { : ; }
C=$HOME/bin/context && [ -f $C ] && $C awk

FILE=${1-data1}
pl " Input data $FILE:"
cat $FILE

pl " Results:"
# awk -F"[ v]" 'a[$1]+0<$3+0{a[$1]=$3} END{for(i in a) print i" v"a[i]}' $FILE
awk -F"[ v.]" '$3+0==vleft[$1]+0 && $4"">vright[$1]"" {vright[$1]=$4} $3+0>vleft[$1]+0 {vleft[$1]=$3;vright[$1]=$4} END {for(i in vleft) print i" v"vleft[i]"."vright[i]}' $FILE

exit 0

producing:

Code:

% ./user2

Environment: LC_ALL = C, LANG = C
(Versions displayed with local utility "version")
OS, ker|rel, machine: Linux, 2.6.26-2-amd64, x86_64
Distribution        : Debian GNU/Linux 5.0.8 (lenny) 
bash GNU bash 3.2.39
awk GNU Awk 3.1.5

-----
 Input data data1:
d v4.0.9
d v4.0.10
a v1.0
a v1.1
a v1.2
b v2.1
b v2.2
b v2.21
b v3.0
c v3.10
c v3.9

-----
 Results:
a v1.2
b v3.0
c v3.9
d v4.0

That does not look correct to me. Did I paste your code faithfully? Are your results different?

Best wishes ... cheers, drl

---------- Post updated at 09:15 ---------- Previous update was at 09:08 ----------

Hi.

With alister's correction:

Code:

#!/usr/bin/env bash

# @(#) user2	Demonstrate proposed awk solution for "version" strings.

pe() { for _i;do printf "%s" "$_i";done; printf "\n"; }
pl() { pe;pe "-----" ;pe "$*"; }
db() { ( printf " db, ";for _i;do printf "%s" "$_i";done;printf "\n" ) >&2 ; }
db() { : ; }
C=$HOME/bin/context && [ -f $C ] && $C awk

FILE=${1-data1}
pl " Input data $FILE:"
cat $FILE

pl " Results:"
# awk -F"[ v]" 'a[$1]+0<$3+0{a[$1]=$3} END{for(i in a) print i" v"a[i]}' $FILE
# awk -F"[ v.]" '$3+0==vleft[$1]+0 && $4"">vright[$1]"" {vright[$1]=$4} $3+0>vleft[$1]+0 {vleft[$1]=$3;vright[$1]=$4} END {for(i in vleft) print i" v"vleft[i]"."vright[i]}' $FILE
awk -F"[ v.]" '$3+0==vleft[$1]+0 && $4+0>vright[$1]+0 {vright[$1]=$4} $3+0>vleft[$1]+0 {vleft[$1]=$3;vright[$1]=$4} END {for(i in vleft) print i" v"vleft[i]"."vright[i]}' $FILE

exit 0

producing:

Code:

% ./user2

Environment: LC_ALL = C, LANG = C
(Versions displayed with local utility "version")
OS, ker|rel, machine: Linux, 2.6.26-2-amd64, x86_64
Distribution        : Debian GNU/Linux 5.0.8 (lenny) 
bash GNU bash 3.2.39
awk GNU Awk 3.1.5

-----
 Input data data1:
d v4.0.9
d v4.0.10
a v1.0
a v1.1
a v1.2
b v2.1
b v2.2
b v2.21
b v3.0
c v3.10
c v3.9

-----
 Results:
a v1.2
b v3.0
c v3.10
d v4.0

Seems OK for 2-part version strings ... cheers, drl

drl

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