Just a side note: AFAIK the -v<varname> (with no space between -v and <varname>) is a GNU awk extension, other awk implementations (new awk etc) support the other version: -v <varname> (with a space).
Thanks - don't think I've come across this before. Seems having the space might turn out to be more portable. AIX 5.3 doesn’t have any trouble with the space missing, so it's not exclusively a GNU awk feature.
The usage string certainly shows a space:
Also interesting to note that awk and nawk on AIX 5.3 are the same binary
This User Gave Thanks to Chubler_XL For This Post:
I'm trying to delete files that were created/modified in the year 2005 that we compressed and have the .Z extension on them. I tried using the awk utility but the syntax is incorrect. I don't know how to use a wildcard to capture all the compressed files. Here's the code I used
( ls -lR |... (5 Replies)
Hi All,
I want to get those the files which were created before 20 days.
Say, we have two server, remote server and local server.
I want to get only 20 days older files from remote server to my local server.
I have used following code for ftp:
(echo "
user ${USERNAME}... (2 Replies)
can someone provide a command to delete files by year? I have several files created last year 2009.
Im trying to list first ls -lrt | grep '/2009/ {print $10}' by it returns no result.
Pls advise (2 Replies)
I have to retain only 1 day files in my system an I have to delete all the other files which are older than 24 hrs. Please let me know the option I have to give in the find -mtime command. (3 Replies)
Hi
I have lot of files and subdirectories inside a directory which are created in the years 2006, 2007, 2008, 2009 and 2010.
I want to delete all the files and subdirectories belonging to the year 2006 alone.
How can I do that ? (5 Replies)
Hi All,
how can i delete files from my Unix directory on the basis of year, i have files from 2001 to till 2014, but from their, i have to delete only 2013 file.Below is my file name
rwxrwxrwx 1 guopt users 5169 Jul 12 00:30 grt592_20130712003000.SAP
Thanks
Kki (2 Replies)
Hi. There is a process which creates log files in the below naming format processname.20140425.log processname1.20140425.log And in this path along with these logs there are other files which have the timestamp from 2012 and i want to have a script in place to delete only the above log files... (13 Replies)
I have more than 200K files created in year 2017 under directory having size of 50GB.
I want to all these files in one shot.
Is there any faster option available with find command to delete all these file ? (6 Replies)
Discussion started by: sp23029
6 Replies
LEARN ABOUT DEBIAN
igawk
IGAWK(1) Utility Commands IGAWK(1)NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)