Below code is for to take the backup of database by daily time stamp. I need vital help to make my script automatic sending me email if it sucess or fail.
I want to put if conditions to check the logfile follwing things are
Hello,
I have a file as follows:
col no:1 2 3 4 5 6 7 8 9 10 11
a 4 226 226 ch:95024048-95027592, 1y224 of 3545 223 224 ident
b 53 235 235 ch:148398-148401255, 1y184 of 3187 180 186 ident
awk... (3 Replies)
Guys, Im trying to have a script that evaluates multiple conditions :
test.sh:
if
then
echo "host $1"
else
if
then
echo "host $1"
else
echo $1 not valid
exit 1
fi
when I do
./test.sh brazil1
I get: (4 Replies)
./script 89
The script will extract the last digit of the input parameter. example, that is 4. This will be compared to the last digit of the current day of the month ( like day 14; that is 4). A message will displayed on the screen indicating if the digits are the same or not. (1 Reply)
Hi All,
I am new to shell scripting.
Can any one say what is wrong in this if statement, that uses multiple conditions
if
then
***************
else
if ( -z $pcs && "$night_time_calc" > "$night_time" )
then
********************************
... (4 Replies)
Currently this is what I am trying
while || && ]; do
I want to continue if the first condition or both the second and third are true but I am getting a too many arguments error.
Can someone help me out? (5 Replies)
I have this IF working fine, testing if a char is a digit:
if ; then
_VALUE=$_VALUE$_CHAR
else
_ISDIGIT="false"
fi
Then I add a second condition to test if the char is either a digit or a *
if ]; then
_VALUE=$_VALUE$_CHAR
... (11 Replies)
All,
I'm having fighting a losing battle with what I though would be simple.
My goal is this: Show a zenity progress or info dialog until the system obtains an ip address, then close the dialog and continue through the rest of the script.
Right now I've got the following:
ip=`ifconfig |... (2 Replies)
Hi ALL
I have a script where in i need to check for several values in if conditons but when i execute the script it throws error such as "TOO MANY ARGUMENTS"
if
then
msg="BM VAR Issue :: bmaRequestVAR=$bmaRequestVAR , nltBMVAR=$nltBMVAR , bmaResponseVAR=$bmaResponseVAR ,... (10 Replies)
#if
if
then
echo $varNO >> AgriN.csv
fi
done < data
The above script throws error such as integer expression expected. How do i rectify that?? (4 Replies)
I'm using the below one..
#!/bin/ksh
File=$3
if ; then
echo "Script"
elif ] ;then
echo "Passed k or f option"
else "Please check the Input passed"
fi
Command line argument is "k" or -f and file is exist then... (3 Replies)
Discussion started by: Roozo
3 Replies
LEARN ABOUT PHP
datetime.modify
DATETIME.MODIFY(3) 1 DATETIME.MODIFY(3)DateTime::modify - Alters the timestamp
Object oriented style
SYNOPSIS
public DateTime DateTime::modify (string $modify)
DESCRIPTION
Procedural style
DateTime date_modify (DateTime $object, string $modify)
Alter the timestamp of a DateTime object by incrementing or decrementing in a format accepted by strtotime(3).
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $modify
-A date/time string. Valid formats are explained in Date and Time Formats.
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
CHANGELOG
+--------+---------------------------------------------------+
|Version | |
| | |
| | Description |
| | |
+--------+---------------------------------------------------+
| 5.3.6 | |
| | |
| | Absolute date/time statements now take effect. |
| | Previously, only relative parts were used. |
| | |
| 5.3.0 | |
| | |
| | Changed the return value on success from NULL to |
| | DateTime. |
| | |
+--------+---------------------------------------------------+
EXAMPLES
Example #1
DateTime.modify(3) example
Object oriented style
<?php
$date = new DateTime('2006-12-12');
$date->modify('+1 day');
echo $date->format('Y-m-d');
?>
Procedural style
<?php
$date = date_create('2006-12-12');
date_modify($date, '+1 day');
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2006-12-13
Example #2
Beware when adding or subtracting months
<?php
$date = new DateTime('2000-12-31');
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
$date->modify('+1 month');
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
SEE ALSO strtotime(3), DateTime.add(3), DateTime.sub(3), DateTime.setDate(3), DateTime.setISODate(3), DateTime.setTime(3), DateTime.setTimes-
tamp(3).
PHP Documentation Group DATETIME.MODIFY(3)