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Printing nth and n+1th line after a pattern match
Post 302658781 by senthilkumark on Wednesday 20th of June 2012 03:12:15 AM
06-20-2012
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folks..
i need a simple one liner to extract data from between the (n)th and (n+1)th instance of a line in a 2 colum file.
eg....for n=3 i should get back
0 1
4 6
help would be much appreciated.
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##################
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0 3
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LEARN ABOUT V7
zgrep
ZGREP(1) General Commands Manual ZGREP(1) NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)