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Top Forums UNIX for Dummies Questions & Answers Compare values of fields from same column with awk Post 302658267 by jawsnnn on Tuesday 19th of June 2012 05:30:26 AM
Old 06-19-2012
If using shell script is an option

Code:
#!/bin/ksh
cnt=$(awk -F'|' '{print NF;exit}' 1)
for i in {1..$(expr ${cnt} - 1)}
do
  field=$(cut -d'|' -f${i} 1 | sort -u | tr '\n' ',' | sed 's/,$//g')
  printf ${field}'|'
done
field=$(cut -d'|' -f${cnt} 1 | sort -u | tr '\n' ',' | sed 's/,$//g')
printf ${field}"\n"

 

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DB2_FIELD_TYPE(3)							 1							 DB2_FIELD_TYPE(3)

db2_field_type - Returns the data type of the indicated column in a result set

SYNOPSIS
string db2_field_type (resource $stmt, mixed $column) DESCRIPTION
Returns the data type of the indicated column in a result set. PARAMETERS
o $stmt - Specifies a statement resource containing a result set. o $column - Specifies the column in the result set. This can either be an integer representing the 0-indexed position of the column, or a string containing the name of the column. RETURN VALUES
Returns a string containing the defined data type of the specified column. If the specified column does not exist in the result set, db2_field_type(3) returns FALSE. SEE ALSO
db2_field_display_size(3), db2_field_name(3), db2_field_num(3), db2_field_precision(3), db2_field_scale(3), db2_field_width(3). PHP Documentation Group DB2_FIELD_TYPE(3)
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