06-15-2012
Trouble with passing variable to sed
Here is my code
#!/bin/bash
username=gnowicki
sed '$s/$/ $username/' < sshd_config 1 <> sshd_config
what this is supposed to do is take the name gnowicki and put it at the end of the last line of the sshd_config and it works except not using the variable, if I put the name "gnowicki" where "$variable" is it puts gnowicki at the end of the line correctly but if I put "$username" it will put "$username" in the sshd_config file and I only want what the variable equals.
what do I need to do?
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sftp-server
sftp-server(1M) System Administration Commands sftp-server(1M)
NAME
sftp-server - SFTP server subsystem
SYNOPSIS
/usr/lib/ssh/sftp-server
DESCRIPTION
sftp-server implements the server side of the SSH File Transfer Protocol as defined in the IETF draft-ietf-secsh-filexfer.
sftp-server is a subsystem for sshd(1M) and must not be run directly. There are no options or config settings.
To enable the sftp-server subsystem for sshd add the following to /etc/ssh/sshd_config:
Subsystem sftp /usr/lib/ssh/sftp-server
See sshd_config(4) for a description of the format and contents of that file.
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SEE ALSO
sftp(1), ssh(1), ssh-add(1), ssh-keygen(1), sshd(1M), sshd_config(4), attributes(5)
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