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Top Forums UNIX for Advanced & Expert Users Finding/Grep on files with date and hour in the file name Post 302655215 by rangarasan on Wednesday 13th of June 2012 01:51:09 AM
Old 06-13-2012
find

Hi,
Try this one,
Code:
cd DATA
find . -name "*' | awk '/^\.\/2012-01-0[1-9]/{print;}'|xargs -I '{}' grep -l 'PQRS' {}

here i am listing all the files from jan 01-09 and then grepping for pattern, if found just displays the file name..
Cheers,
Ranga:-)
 

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ZGREP(1)						    BSD General Commands Manual 						  ZGREP(1)

NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...] zegrep [grep-flags] [--] pattern [file ...] zfgrep [grep-flags] [--] pattern [file ...] DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1). The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern argument. zegrep calls egrep(1), while zfgrep calls fgrep(1). EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0. SEE ALSO
egrep(1), fgrep(1), grep(1), gzip(1), zcat(1) AUTHORS
Thomas Klausner <wiz@NetBSD.org> BSD
December 28, 2003 BSD
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