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Full Discussion: Convert hex to decimal
Top Forums Shell Programming and Scripting Convert hex to decimal Post 302652363 by Skrynesaver on Thursday 7th of June 2012 04:28:47 AM
Old 06-07-2012
The following works:
Code:
perl -e '
$hex="0c07ac14001676"; 
while($hex=~/(..)/g){
    push @values, $1;
};
for (@values){
    $_=hex($_);
}
print join(",",@values),"\n";'
12,7,172,20,0,22,118

This User Gave Thanks to Skrynesaver For This Post:
 

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CORE(3pm)						 Perl Programmers Reference Guide						 CORE(3pm)

NAME
CORE - Pseudo-namespace for Perl's core routines SYNOPSIS
BEGIN { *CORE::GLOBAL::hex = sub { 1; }; } print hex("0x50")," "; # prints 1 print CORE::hex("0x50")," "; # prints 80 DESCRIPTION
The "CORE" namespace gives access to the original built-in functions of Perl. There is no "CORE" package, and therefore you do not need to use or require an hypothetical "CORE" module prior to accessing routines in this namespace. A list of the built-in functions in Perl can be found in perlfunc. OVERRIDING CORE FUNCTIONS
To override a Perl built-in routine with your own version, you need to import it at compile-time. This can be conveniently achieved with the "subs" pragma. This will affect only the package in which you've imported the said subroutine: use subs 'chdir'; sub chdir { ... } chdir $somewhere; To override a built-in globally (that is, in all namespaces), you need to import your function into the "CORE::GLOBAL" pseudo-namespace at compile time: BEGIN { *CORE::GLOBAL::hex = sub { # ... your code here }; } The new routine will be called whenever a built-in function is called without a qualifying package: print hex("0x50")," "; # prints 1 In both cases, if you want access to the original, unaltered routine, use the "CORE::" prefix: print CORE::hex("0x50")," "; # prints 80 AUTHOR
This documentation provided by Tels <nospam-abuse@bloodgate.com> 2007. SEE ALSO
perlsub, perlfunc. perl v5.12.1 2010-04-26 CORE(3pm)
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