05-29-2012
Thanks for the replies... I just wonder if the date is a leap year...
example: 20120229... and there is no 20090229... in this case it should be the next day 20090301 is subtracted by 3 years
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LEARN ABOUT MOJAVE
datetime::leapsecond5.18
DateTime::LeapSecond(3) User Contributed Perl Documentation DateTime::LeapSecond(3)
NAME
DateTime::LeapSecond - leap seconds table and utilities
VERSION
version 1.06
SYNOPSIS
use DateTime;
use DateTime::LeapSecond;
print "Leap seconds between years 1990 and 2000 are ";
print DateTime::Leapsecond::leap_seconds( $utc_rd_2000 ) -
DateTime::Leapsecond::leap_seconds( $utc_rd_1990 );
DESCRIPTION
This module is used to calculate leap seconds for a given Rata Die day. It is used when DateTime.pm cannot compile the XS version of this
code.
This library is known to be accurate for dates until December 2009.
There are no leap seconds before 1972, because that's the year this system was implemented.
o leap_seconds( $rd )
Returns the number of accumulated leap seconds for a given day, in the range 0 .. 22.
o extra_seconds( $rd )
Returns the number of leap seconds for a given day, in the range -2 .. 2.
o day_length( $rd )
Returns the number of seconds for a given day, in the range 86398 .. 86402.
SEE ALSO
<http://hpiers.obspm.fr/eop-pc/earthor/utc/leapsecond.html>
http://datetime.perl.org
AUTHOR
Dave Rolsky <autarch@urth.org>
COPYRIGHT AND LICENSE
This software is Copyright (c) 2013 by Dave Rolsky.
This is free software, licensed under:
The Artistic License 2.0 (GPL Compatible)
perl v5.18.2 2017-10-06 DateTime::LeapSecond(3)