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Top Forums Shell Programming and Scripting Setting default permissions without umask or cron jobs Post 302646023 by Karunamon on Thursday 24th of May 2012 11:46:02 AM
Old 05-24-2012
I don't think I can do that, since the default file mask is 666. I can only reduce from there, using umask, correct? I need a way to add that final 1.
 

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umask(2)							System Calls Manual							  umask(2)

NAME
umask - Sets and gets the value of the file creation mask SYNOPSIS
#include <sys/types.h> #include <sys/stat.h> mode_t umask ( mode_t cmask ); STANDARDS
Interfaces documented on this reference page conform to industry standards as follows: umask(): POSIX.1, XPG4, XPG4-UNIX Refer to the standards(5) reference page for more information about industry standards and associated tags. PARAMETERS
Specifies the value of the file mode creation mask. DESCRIPTION
The umask() function sets the file mode creation mask of the process to the value of the cmask parameter and returns the previous value of the mask. The cmask parameter is constructed by logically ORing file permission bits defined in the sys/mode.h header file. Whenever a file is created (by the open(), mkdir(), or mknod() function), all file permission bits set in the file mode creation mask are cleared in the mode of the created file. This clearing lets users restrict the default access to their files. The mask is inherited by child processes. RETURN VALUES
Upon successful completion, the previous value of the file mode creation mask is returned. RELATED INFORMATION
Commands: chmod(1), mkdir(1), Bourne shell sh(1b), POSIX shell sh(1p), umask(1) Functions: chmod(2), mkdir(2), mknod(2), open(2), stat(2) Standards: standards(5) delim off umask(2)
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