im having trouble doing this:
i have a variable with 2 characters repeating e.g. aababbbaaaababaabbaabbba
is there a way i can search the variable for a's and b's and then change a's to b's and b's to a's?
im guessing its like getting the 1's compliment of the string
im doing this in... (2 Replies)
Greetings,
I am doing something that I don't know if it is possible...
I have a file with a line looks like this:
<%s \n%s / %s \n%s \n>
and I am trying to replace this line with
<%s \n%s \n%s / %s \n%s \n>
in Shell script with sed command...
StringToReplace='%s \n%s / %s \n%s \n'... (2 Replies)
I need to do the following:
text in the format of: ADDRESS=abcd123:1111
- abcd123:1111 is different on every system.
replace with: ADDRESS=localhost:2222
sed 's/ADDRESS=<What do I use here?>/ADDRESS=localhost:2222/g'
Everything I've tried ends up with:
... (3 Replies)
How can I replace the follong text including to number 7000?
cat tmp0.txt
Winston (UK) Wong
I would the 7000 to replace Winston (UK) Wong.
I fail with method below:
sed ' s /Winston\(UK\)Wong/7000 tmp0.txt' (1 Reply)
Hi All,
I have a text file that contains
I1SP2 *=*=Y=M=D001D
My requirement is to replace all occurrence of =* to =Z
expected o/p is I1SP2 *=Z=Y=M=D001D
I have tried with
sed 's/=*/=Z/g' file
sed 's!\=*!\=Z/g' file
sed 's!\=*!\=Z!g' file
sed 's!\=\*!\=Z!g' file
but its not... (3 Replies)
Hi all
I got test.test.test and need
test.test\.test *
I need the backslash before the last dot in the line
I tried
echo test.test.test | sed 's/\./\\./g'
but it gives me
test\.test\.test
Thanks (7 Replies)
Hi Gurus,
I have a requirement which needs to pass a parameter when calling the script, using this parameter to find a file name stored in master file. then read the file content. the issue is in the file name has a special character "$". don't know how to handle this. below is example:
the... (10 Replies)
hi all,
i'd like to modify a file with sed , i want to substuite a char "-" with "/"
how can i do this?
Thanks for all
regards
Francesco (16 Replies)
Discussion started by: Francesco_IT
16 Replies
LEARN ABOUT CENTOS
paps
PAPS(1) General Commands Manual PAPS(1)NAME
paps - UTF-8 to PostScript converter using Pango
SYNOPSIS
paps [options] files...
DESCRIPTION
paps reads a UTF-8 encoded file and generates a PostScript language rendering of the file. The rendering is done by creating outline curves
through the pango ft2 backend.
OPTIONS
These programs follow the usual GNU command line syntax, with long options starting with two dashes (`-'). A summary of options is
included below.
--landscape
Landscape output. Default is portrait.
--columns=cl
Number of columns output. Default is 1.
--font=desc
Set the font description. Default is Monospace 12.
--rtl Do rtl layout.
--paper ps
Choose paper size. Known paper sizes are legal, letter, a4. Default is A4.
--bottom-margin=bm
Set bottom margin in postscript points (1/72 inch). Default is 36.
--top-margin=tm
Set top margin. Default is 36.
--left-margin=lm
Set left margin. Default is 36.
--right-margin=rm
Set right margin. Default is 36.
--help Show summary of options.
--header
Draw page header for each page.
--markup
Interpret the text as pango markup.
--encoding=ENCODING
Assume the documentation encoding is ENCODING.
--lpi Set the lines per inch. This determines the line spacing.
--cpi Set the characters per inch. This is an alternative method of specifying the font size.
--stretch-chars
Indicates that characters should be stretched in the y-direction to fill up their vertical space. This is similar to the texttops
behaviour.
AUTHOR
paps was written by Dov Grobgeld <dov.grobgeld@gmail.com>.
This manual page was written by Lior Kaplan <kaplan@debian.org>, for the Debian project (but may be used by others).
April 17, 2006 PAPS(1)