Hello.
Consider the following magic words:
# ls `which adduser`
ls: /usr/sbin/adduser: No such file or directory
#
Hmmm...
Then:
# ls /usr/sbin/adduser
/usr/sbin/adduser
#
Now what?
Unforunately this little sniippet is used in my debian woody server's mysql pre install script.... (2 Replies)
Hi,
I use the command
ls a\b\c\*.txt
from the command line on HP UNIX and it works fine - It lists all files matching *.txt in the a\b\c directory
When embeded in a ksh script
`ls a\b\c\*.txt`
it does not work - I get *.txt not found (even though there are files)
I tried... (10 Replies)
Portion of my script below :
if ; then
NUMBEROFFEILDS=`cat ${BASE_SCRIPT_LOC}/standardfilecleanup.lst|grep -w ${db_file_path}|awk -F: '{print NF}'`
COUNT=4
while ; do
awk_var="$"`echo $COUNT`
file_name1=`cat ${BASE_SCRIPT_LOC}/standardfilecleanup.lst|grep -w... (1 Reply)
I am trying to find only those entries where 7018 and another number appear in the end of the line.
7018 2828 1423 2351
7018 2828 14887
2828 7018 1222
123 7018 1487
I am looking for a way to generate only the last two lines. I was trying to do just "grep '7018{1,5}" but it does not... (5 Replies)
Hi!
Been working on a script and I've been having a problem. I've finally narrowed it down to this variable I'm setting:
servername=$(awk -v FS=\/ '{ print $7 } blah.txt | sed 's\/./-/g' | awk -v FS=\- '{print $1}')"
This will essentially pare down a line like this:
... (7 Replies)
I need to sort through a volume that contains video files by access time and delete files that have not been accessed over x days. I have to use the access time as video files are originals that do not get modified, just read
Testing commands on a local test folder...
$ date
Wed Sep 28... (10 Replies)
Hi. I am trying to start a script on my router that will execute even if i log off. To execute the script I write:
nohup ./dslconnection > dslstat.out 2>&1 &
It starts the job:
21968 admin 1604 S /bin/ash ./dslconnection
The problem is that when I log back in the job has been... (6 Replies)
Hi,
I have prepared a script and trying to execute it but not getting expected output. Could you please help and advise what is going wrong.
"If else" part in below script is not working basically.
I am running it on HP-UX.
for i in slpd puma sfmdb
do
echo "******\t$i\t*******"
echo... (10 Replies)
I ran into the following and still do not understand entirely the rationale behind this. If someone could explain why things are as they are I'd be thankful.
The following was tested on AIX 7.1 with ksh88, but i suspect that to be ubiquitous. In an installation routine i had to create a set of... (6 Replies)
Discussion started by: bakunin
6 Replies
LEARN ABOUT DEBIAN
pmfunc
PMFUNC(1p) User Contributed Perl Documentation PMFUNC(1p)NAME
pmfunc - cat out a function from a module
DESCRIPTION
Given a fully-qualified function, this program opens up the file and attempts to cat out the source for that function.
EXAMPLES
$ pmfunc Cwd::getcwd
sub getcwd
{
abs_path('.');
}
RESTRICTIONS
Only subroutines that are defined in the normal fashion are seen, since a simple pattern-match is what does the extraction. Those loaded
other ways, such as via AUTOLOAD, typeglob aliasing, or in an "eval", will all necessarily be missed.
This is mostly here for people who are too lazy to type
sed '/^sub getcwd/,/}/p' `pmpath Cwd`
or
perl -ne 'print if /^subs+getcwd/ .. /}/' `pmpath Cwd`
RESTRICTIONS SEE ALSO AUTHORS and COPYRIGHTS
Copyright (C) 1999 Tom Christiansen.
Copyright (C) 2006-2008 Mark Leighton Fisher.
This is free software; you can redistribute it and/or modify it under the terms of either: (a) the GNU General Public License as published
by the Free Software Foundation; either version 1, or (at your option) any later version, or (b) the Perl "Artistic License". (This is the
Perl 5 licensing scheme.)
Please note this is a change from the original pmtools-1.00 (still available on CPAN), as pmtools-1.00 were licensed only under the Perl
"Artistic License".
perl v5.10.1 2010-02-22 PMFUNC(1p)