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Top Forums Shell Programming and Scripting sed replacing specific characters and control characters by escaping Post 302631153 by ijustneeda on Friday 27th of April 2012 12:59:11 AM
Old 04-27-2012
sed replacing specific characters and control characters by escaping

Code:
sed -e "s/[\.\/\%'=:\(\)\`_\"\@\;\+\*\#\$\?\!]/ /g" old.txt > new.txt

While I do know some control characters need to be escaped, can normal characters also be escaped and still work the same way? Basically I do not know all control characters that have a special meaning, for example, ?, ., % have a meaning and have to be escaped to be replaced.

Does the above sed work as expected to replace all of the below characters with a space?
Code:
 ,
  .
  @
  /
  #
  :
  (
  )
  '
  *
  %
  $
  +
  ?
  _
  =
  "
  !
  ;


Last edited by Franklin52; 04-27-2012 at 03:45 AM.. Reason: Please use code tags
 

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load_dat_font(3alleg4)						  Allegro manual					    load_dat_font(3alleg4)

NAME
load_dat_font - Loads a FONT from an Allegro datafile. SYNOPSIS
#include <allegro.h> FONT *load_dat_font(const char *filename, RGB *pal, void *param) DESCRIPTION
Loads a FONT from an Allegro datafile. You can set param parameter to point to an array that holds two strings that identify the font and the palette in the datafile by name. The first string in this list is the name of the font. You can pass NULL here to just load the first font found in the datafile. The second string can be used to specify the name of the palette associated with the font. This is only returned if the pal parameter is not NULL. If you pass NULL for the name of the palette, the last palette found before the font was found is returned. You can also pass NULL for param, which is treated as if you had passed NULL for both strings separately. In this case, the function will simply load the first font it finds from the datafile and the palette that precedes it. For example, suppose you have a datafile named `fonts.dat' with the following contents: FONT FONT_1_DATA FONT FONT_2_DATA FONT FONT_3_DATA PAL FONT_1_PALETTE PAL FONT_2_PALETTE Then the following code will load FONT_1_DATA as a FONT and return FONT_1_PALETTE as the palette: FONT *f; PALETTE pal; char *names[] = { "FONT_1_DATA", "FONT_1_PALETTE" } f = load_dat_font("fonts.dat", pal, names); If instead you want to load the second font, FONT_2, from the datafile, you would use: FONT *f; PALETTE pal; char *names[] = { "FONT_2_DATA", "FONT_2_PALETTE" } f = load_dat_font("fonts.dat", pal, names); If you want to load the third font, but not bother with a palette, use: FONT *f; char *names[] = { "FONT_3_DATA", NULL } f = load_dat_font("fonts.dat", NULL, names); RETURN VALUE
Returns a pointer to the font or NULL on error. Remember that you are responsible for destroying the font when you are finished with it to avoid memory leaks. SEE ALSO
register_font_file_type(3alleg4), load_font(3alleg4) Allegro version 4.4.2 load_dat_font(3alleg4)
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