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Top Forums Shell Programming and Scripting echo the NAME of the variable Post 302630245 by neutronscott on Wednesday 25th of April 2012 02:49:24 PM
Old 04-25-2012
Did you see my post update about indirection? In this way you actually pass variables names rather than values, and use the special ${!} notation to expand the value of the variable inside the variable ...

edit: oh nevermind, saw your title "hundreds of vars"... indeed an array is the way to go. target is bash3 or bash4? with bash3 you'd need two separate arrays, one would keep the "key" and the other the "value",
in bash4 you have associative arrays, such that array[key]=val. example for bash3:

Code:
[mute@geek ~]$ keys=(varA varB varC varD)
[mute@geek ~]$ vals=(AAA1 BBB1 CCC1 DDD1)
[mute@geek ~]$ for i in "${!keys[@]}"; do echo "${keys[i]} = ${vals[i]}"; done
varA = AAA1
varB = BBB1
varC = CCC1
varD = DDD1


Last edited by neutronscott; 04-25-2012 at 03:55 PM..
 

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ARRAY_REPLACE(3)							 1							  ARRAY_REPLACE(3)

array_replace - Replaces elements from passed arrays into the first array

SYNOPSIS
array array_replace (array $array1, array $array2, [array $...]) DESCRIPTION
array_replace(3) replaces the values of $array1 with values having the same keys in each of the following arrays. If a key from the first array exists in the second array, its value will be replaced by the value from the second array. If the key exists in the second array, and not the first, it will be created in the first array. If a key only exists in the first array, it will be left as is. If several arrays are passed for replacement, they will be processed in order, the later arrays overwriting the previous values. array_replace(3) is not recursive : it will replace values in the first array by whatever type is in the second array. PARAMETERS
o $array1 - The array in which elements are replaced. o $array2 - The array from which elements will be extracted. o $... - More arrays from which elements will be extracted. Values from later arrays overwrite the previous values. RETURN VALUES
Returns an array, or NULL if an error occurs. EXAMPLES
Example #1 array_replace(3) example <?php $base = array("orange", "banana", "apple", "raspberry"); $replacements = array(0 => "pineapple", 4 => "cherry"); $replacements2 = array(0 => "grape"); $basket = array_replace($base, $replacements, $replacements2); print_r($basket); ?> The above example will output: Array ( [0] => grape [1] => banana [2] => apple [3] => raspberry [4] => cherry ) SEE ALSO
array_replace_recursive(3), array_merge(3). PHP Documentation Group ARRAY_REPLACE(3)
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