This an interesting puzzle because I for one cannot come up with a simple solution which works on all modern unix and Linux O/S (the O/S was not stated) ... and which uses "find .... -exec".
In the commercial world we would use a construct which lets us do a sequence of commands within a do-done loop:
I realise that this does not match you requirement because there is no "-exec" on the "find".
Ignoring those versions of the "find" command which support more than one command with "-exec", one must look at what "-exec" could run.
Hmm it could run a simple Shell script which displayed the filename and then displayed the first line of the file in question.
Just an idea, other posters may have better ideas.
Last edited by methyl; 04-22-2012 at 05:30 PM..
Reason: typos
Hi All,
How can the head command be used to extract only a particular line.
By default head -n filename displays the first n lines. I want only the nth line.
I couldn't get it from forum search.
Thanks,
Sumesh (6 Replies)
Yes , I have to find a file in unix without using any find or where commands.Any pointers for the same would be very helpful as i am beginner in shell scritping and need a solution for the same.
Thanks in advance.
Regards
Jatin Jain (10 Replies)
Hi friends,I am new to unix and this is really a dummy question.but please help me out.
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