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Top Forums Shell Programming and Scripting Remove newline character or join the broken record Post 302625809 by chidori on Wednesday 18th of April 2012 10:25:41 AM
Old 04-18-2012
I am trying to understand this code. please help

I have removed the next statement and trying to understand how the code works.. below i have given i how i have understood this code. please correct me if i am wrong.

Code:
bash-3.00# awk '/{}$/{print}{printf "%s ",$0;}' test.txt

1[|]2[|]3[|]4[|]5[|]6[|]7 [|]a[|]b[|]c[|]d{}
[|]a[|]b[|]c[|]d{} 1[|]2[|]3[|]4[|]sss[|]ss as6[|]7 [|]a[|]b[|]c[|]d{}
[|]a[|]b[|]c[|]d{} 1[|]2[|]dsad3[|]dad 4[|]sdad5[|]6[|]7 [|]a[|]b[|dsad]c[|]dsadd{}
[|]a[|]b[|dsad]c[|]dsadd{}


so here the pattern statement is /{}$/
the action statement is {print} ( This print statement will execute if the pattern matched successfully. else this wont executed )
{printf "%s ",$0;} ( This statement will execute throught the script. it doesnt come under any condition )

Code:
line 1 : 1[|]2[|]3[|]4[|]5[|]6[|]7

the pattern {}$ doesnt match this line so the {print} statement doesnt execute.
But the {printf "%s ",$0;} executes and prints the same line1 as thats the current record in processing.

Now the first line has been read and awk moves on to the next line

Code:
line 2 : [|]a[|]b[|]c[|]d{}

the pattern {}$ does match and {print} statement gets executed.

Now awk should again print the line 2 as there is {printf "%s ",$0;} right ? how does it move to next record ?
 

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REGEXP(6)							   Games Manual 							 REGEXP(6)

NAME
regexp - regular expression notation DESCRIPTION
A regular expression specifies a set of strings of characters. A member of this set of strings is said to be matched by the regular expression. In many applications a delimiter character, commonly bounds a regular expression. In the following specification for regular expressions the word `character' means any character (rune) but newline. The syntax for a regular expression e0 is e3: literal | charclass | '.' | '^' | '$' | '(' e0 ')' e2: e3 | e2 REP REP: '*' | '+' | '?' e1: e2 | e1 e2 e0: e1 | e0 '|' e1 A literal is any non-metacharacter, or a metacharacter (one of .*+?[]()|^$), or the delimiter preceded by A charclass is a nonempty string s bracketed [s] (or [^s]); it matches any character in (or not in) s. A negated character class never matches newline. A substring a-b, with a and b in ascending order, stands for the inclusive range of characters between a and b. In s, the metacharacters an initial and the regular expression delimiter must be preceded by a other metacharacters have no special meaning and may appear unescaped. A matches any character. A matches the beginning of a line; matches the end of the line. The REP operators match zero or more (*), one or more (+), zero or one (?), instances respectively of the preceding regular expression e2. A concatenated regular expression, e1e2, matches a match to e1 followed by a match to e2. An alternative regular expression, e0|e1, matches either a match to e0 or a match to e1. A match to any part of a regular expression extends as far as possible without preventing a match to the remainder of the regular expres- sion. SEE ALSO
awk(1), ed(1), sam(1), sed(1), regexp(2) REGEXP(6)
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