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Top Forums UNIX for Dummies Questions & Answers How to run multiple command in a single line? Post 302623735 by agama on Saturday 14th of April 2012 12:43:02 PM
Old 04-14-2012
Replace the pipe (|) with a semicolon like this:

Code:
cd dir-name; ls -lrt

It will change the directory and then list it's contents.
 

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PIPE(3) 						     Library Functions Manual							   PIPE(3)

NAME
pipe - two-way interprocess communication SYNOPSIS
bind #| dir dir/data dir/ctl dir/data1 dir/ctl1 DESCRIPTION
An attach(5) of this device allocates two new streams joined at the device end. X/data and x/ctl are the data and control channels of one stream and x/data1 and x/ctl1 are the data and control channels of the other stream. Data written to one channel becomes available for reading at the other. Write boundaries are preserved: each read terminates when the read buffer is full or after reading the last byte of a write, whichever comes first. Written data is buffered in kernel stream blocks. The writer will block once the stream is full, typically after 32768 bytes or 16 writes. The writer will resume once the stream is less than half full. If there are multiple writers, each write is guaranteed to be available in a contiguous piece at the other end of the pipe. If there are multiple readers, each read will return data from only one write. The pipe(2) system call performs an attach of this device and returns file descriptors to the new pipe's data and data1 files. The files are open with mode ORDWR. SEE ALSO
pipe(2) SOURCE
/sys/src/9/port/devpipe.c PIPE(3)
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