04-10-2012
Please post what Operating System and version you are using and what Shell you use.
Please post the code you tried and what happened.
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
Please let me know how to cut first four characters from a line in UNIX after grepping the file.. (5 Replies)
Discussion started by: kaushikraman
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2. Shell Programming and Scripting
Hi All,
Need to convert file names to upper case using tr command in Unix.
In a folder -> /apps/dd01/misc
there are two files like:
pi-abcd567sd.pdf
pi-efgh1.pdf
The output of should be like:
pi-ABCD567SD.pdf
pi-EFGH1.pdf
I have used the command to work as below:
for f... (3 Replies)
Discussion started by: a1_win
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3. Shell Programming and Scripting
Guys,
can you help me in doing cut first 21 and 32-35 characters from file.
I tried with cut -c to cut first 21 characters ,It is succeeded.
But i need both first 21 and 32-35. (1 Reply)
Discussion started by: mohan_xunil
1 Replies
4. Shell Programming and Scripting
Hi Gurus,
I am trying to execute the below command. However the output shows the value + path of the folder where the command is being executed. But I am only interested in the value but not the path.
du -hs /aps/inf/SeLogs
when I execute the above command, output is
32G... (5 Replies)
Discussion started by: svajhala
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5. Shell Programming and Scripting
I need to cut the last seven characters of a variable length variable. The variable may be 7 characters or 70. I need to always be able to grab the last 7 characters. I looked at the cut command but it always seems to want to start at the beginning of a line, not the end and count backwards.
... (5 Replies)
Discussion started by: kblawson14
5 Replies
6. Shell Programming and Scripting
Hi,
I would like to cut last 13 characters of a file name and take the rename the file name as follows:
Input:
A.DAT20110517033732
Output:
A.DAT
I have tried the following command and cut last 13 characters.
echo A.DAT20110517033732 | awk '{print substr($0, length($0)-13)}'
... (3 Replies)
Discussion started by: pyaranoid
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7. Shell Programming and Scripting
Hi Everyone,
i have a file 1.txt
<a><a"" dd>aaaaauweopriuew</f><">!(^)!</aa></ff>
<a><a"" dd>bbbbbuweopriuew</f><">!(^*)!</aa></ff>
i know i can use
perl -p -i -e "s/>aaaaa/aa/g" 1.txt
perl -p -i -e "s/>bbbbb/bb/g" 1.txt
to acheive only keep the first two characters of the five characters,... (4 Replies)
Discussion started by: jimmy_y
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8. Shell Programming and Scripting
i have following fixed width text(also has a delimiter)
id;name;age;comments1;comments2;title;date
to get output as
id;name;age;;;title;date (remove comments but keep the delimiter in between)
i use cut -c1-12,22,32-
suppose if i want to insert another ; somewhere like ... (3 Replies)
Discussion started by: petergemeni
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9. Shell Programming and Scripting
helloo
I wonder if there's a way to cut characters out of a string and keep only
the last 2 by using sed.
For example if there's the todays' date:
2012-05-06
and we only want to keep the last 2 characters which are the day.
Is there a quick way to do it with sed? (2 Replies)
Discussion started by: vlm
2 Replies
10. Shell Programming and Scripting
Hello All
I have a file like this
abc.tpt.ctl
bdc.tpt.ctl
cdw.tpt.ctl
I have looped every line using the for Loop, now I want to take each line and cut the .tpt.ctl part of it and store it in a variable and use the variable in same loop.
The part I am stuck at is how do I cut the last... (9 Replies)
Discussion started by: nnani
9 Replies
LEARN ABOUT DEBIAN
blaze-remove
BLAZE-REMOVE(1) BlazeBlogger Documentation BLAZE-REMOVE(1)
NAME
blaze-remove - removes a post or page from the BlazeBlogger repository
SYNOPSIS
blaze-remove [-fipqPV] [-b directory] id...
blaze-remove -h|-v
DESCRIPTION
blaze-remove removes a blog post or a page with the specified id from the BlazeBlogger repository.
OPTIONS
-b directory, --blogdir directory
Allows you to specify a directory in which the BlazeBlogger repository is placed. The default option is a current working directory.
-p, --page, --pages
Tells blaze-remove to remove a page or pages.
-P, --post, --posts
Tells blaze-remove to remove a blog post or blog posts. This is the default option.
-f, --force
Disables requiring manual confirmation of each blog post or page removal. This is the default option.
-i, --interactive
Enables requiring manual confirmation of each blog post or page removal.
-q, --quiet
Disables displaying of unnecessary messages.
-V, --verbose
Enables displaying of all messages. This is the default option.
-h, --help
Displays usage information and exits.
-v, --version
Displays version information and exits.
EXAMPLE USAGE
Remove a blog post:
~]$ blaze-remove 10
Successfully removed the post with ID 10.
Remove a page:
~]$ blaze-remove -p 4
Successfully removed the page with ID 4.
Remove multiple blog posts:
~]$ blaze-remove 10 4 6
Successfully removed the post with ID 10, 4 and 6.
Remove multiple blog posts safely:
~]$ blaze-remove -i 10 4 6
Remove the post with ID 10 titled `Debian and Fedora Packages'? y
Remove the post with ID 4 titled `BlazeBlogger 0.8.0 RC2'? y
Remove the post with ID 6 titled `BlazeBlogger 0.8.1'? y
Successfully removed the post with ID 10, 4 and 6.
SEE ALSO
blaze-config(1), blaze-add(1), blaze-list(1)
BUGS
To report a bug or to send a patch, please, add a new issue to the bug tracker at <http://code.google.com/p/blazeblogger/issues/>, or visit
the discussion group at <http://groups.google.com/group/blazeblogger/>.
COPYRIGHT
Copyright (C) 2008-2011 Jaromir Hradilek
This program is free software; see the source for copying conditions. It is distributed in the hope that it will be useful, but WITHOUT ANY
WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.
Version 1.2.0 2012-03-05 BLAZE-REMOVE(1)