04-10-2012
In that case create an associative array that maps the 2 digits with the desired filename...read/parse each input file record...and output it to the specific filename based on the numerical code.
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1. Shell Programming and Scripting
Hi All,
I have a file like below:
1016D"ddd","343","1299"
1016D"ddd","3564","1299"
1016D"ddd","3297","1393"
1016D"ddd","32989","1527"
1016D"ddd","346498","1652"
2312D"ddd","3269","1652"
2312D"ddd","328","1652"
2312D"ddd","2224","2100"
3444D"ddd","252","2100"
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Dear All,
I would like to split a file of the following format into multiple files based on the number in the 6th column (numbers 1, 2, 3...):
ATOM 1 N GLY A 1 -3.198 27.537 -5.958 1.00 0.00 N
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I have a file with lines something like.
......
123_start
......
.......
123_end
....
.....
456_start
......
.....
456_end
....
.....
789_start
....
....
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Hello, I am using awk to split a file into multiple files using command:
nawk '{
if ( $1 == "<process" )
{
n=split($2, arr, "\"");
file=arr
}
print > file }' processes.xml
<process name="Process1.process">
... (3 Replies)
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Hi,
I've one requirement. I have to split one comma delimited file into multiple files based on one of the column values.
How can I achieve this Unix
Here is the sample data. In this case I have split the files based on date column(c4)
Input file
c1,c2,c3,c4,c5... (1 Reply)
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Good day all
I need some helps,
say that I have data like below, each field separated by a tab
DATE NAME ADDRESS
15/7/2012 LX a.b.c
15/7/2012 LX1 a.b.c
16/7/2012 AB a.b.c
16/7/2012 AB2 a.b.c
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So I have a space delimited file that I'd like to split into multiple files based on multiple column values.
This is what my data looks like
1bc9A02 1 10 1000 FTDLNLVQALRQFLWSFRLPGEAQKIDRMMEAFAQRYCQCNNGVFQSTDTCYVLSFAIIMLNTSLHNPNVKDKPTVERFIAMNRGINDGGDLPEELLRNLYESIKNEPFKIPELEHHHHHH
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I have a requirement to split a huge file to smaller text files based on first four characters which look like
ABCD
1234
DFGH
RREX
:
:
:
:
:
0000
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Hi All,
I have the sales_data.csv file in the directory as below.
SDDCCR; SOM ; MD6546474777 ;05-JAN-16
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I am using below code to split files based on blank lines but it does not work.
awk 'BEGIN{i=0}{RS="";}{x="F"++i;}{print > x;}'
Your help would be highly appreciated
find attachment of sample.txt file (2 Replies)
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LEARN ABOUT DEBIAN
dpkg::interface::storable
Dpkg::Interface::Storable(3) libdpkg-perl Dpkg::Interface::Storable(3)
NAME
Dpkg::Interface::Storable - common methods related to object serialization
DESCRIPTION
Dpkg::Interface::Storable is only meant to be used as parent class for other objects. It provides common methods that are all implemented
on top of two basic methods parse() and output().
BASE METHODS
Those methods must be provided by the object that wish to inherit from Dpkg::Interface::Storable so that the methods provided can work.
$obj->parse($fh, $desc)
This methods initialize the object with the data stored in the filehandle. $desc is optional and is a textual description of the
filehandle used in error messages.
$string = $obj->output($fh)
This method returns a string representation of the object in $string and it writes the same string to $fh (if it's defined).
PROVIDED METHODS
$obj->load($filename)
Initialize the object with the data stored in the file. The file can be compressed, it will be uncompressed on the fly by using a
Dpkg::Compression::FileHandle object. If $filename is "-", then the standard input is read (no compression is allowed in that case).
$obj->save($filename)
Store the object in the file. If the filename ends with a known compression extension, it will be compressed on the fly by using a
Dpkg::Compression::FileHandle object. If $filename is "-", then the standard output is used (data are written uncompressed in that
case).
"$obj"
Return a string representation of the object.
AUTHOR
Raphael Hertzog <hertzog@debian.org>.
1.16.15 2014-06-05 Dpkg::Interface::Storable(3)