Check the permissions of a user
Users enter a user and a path to the directory.
Returns the result is the child folders and files in the folder the user to enter and rights that
that user on the directory.
for example:
suppose we have the Public folder as follows:
If user enter:
-Kenshin
or /home/kenshin/Public
output:
my shell:
but not very feasible, one can help me, help me plzzz, thank very much
What I need to do is: I need to use the grep command to search for pattern in directory and sub-directories. And also I need to show the permission of file been seached by the grep command.
Could any one please suggest me?
-----------------
$> cat file1.txt
A
-----------------... (8 Replies)
hi all,
i have a script (ksh) which reads data from log files, how do i check to see if the user which is executing the script has read permissions to the file ?
thanks in advance. (2 Replies)
Hi - I am trying to send email from unix box but none were delivered. I have tried multiple commands like mailx, mail or sendmail. But none of them worked. can you please let me know how to check if I have the right permissions to send the mail or not? (1 Reply)
hi
i want to display the usernames,usergroups user permissions and user home directory's with in a single command.and possibities are their for getting this output .. (9 Replies)
hello,
I have to write a script to run the other script inside it.So iam planning to write like this?
first check the perimissions of the file.
Alogorthim
----------
if(!filepermissions == execute)
then
echo" Permissions denined"
else
execute the script.
file name is : load_mf.sh... (1 Reply)
i have some question
for example:
suppose we have the Public folder as follows:
https://www.unix.com/attachment.php?attachmentid=2759&stc=1&d=1334070669
If the user enter:
-Kenshin
or /home/kenshin/Public
output: abc: kenshin: rw
my shell:
echo "Enter User:"
read user ... (3 Replies)
Hi,
For a particular set of files, am trying to check if they are writable. i.e., checking whether they are having permissions greater than 755.
Am able to check this using the statement:
"if (os.path.isfile(FILE_PATH) and (os.stat(FILE_PATH).st_mode & 0777) == 0777):"
But the problem here... (0 Replies)
Hi,
For a particular set of files, am trying to check if they are writable. i.e., checking whether they are having permissions greater than 755.
Am able to check this using the statement:
"if (os.path.isfile(FILE_PATH) and (os.stat(FILE_PATH).st_mode & 0777) == 0777):"
But the problem... (1 Reply)
Is there a way to check when the permissions for the file got changed in AIX
IS there some file which logs all these details?
Best regards,
Vishal (4 Replies)
Hello,
I would like to know if it's a good practice to check the file permissions of the contents of a directory before moving them. For example:
mv -- "$directory"/* "$directory"/.* "$directory"/..?* "$destination"The variables $directory and $destination contain the path to an existing... (6 Replies)
Discussion started by: Cacializ
6 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)