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Top Forums Shell Programming and Scripting How to extract portion of a string? Post 302618775 by CarloM on Wednesday 4th of April 2012 11:52:12 AM
Old 04-04-2012
A variation:
Code:
awk -v FS="[ =]" '{ print $3 }' inputfile | xargs -L1 basename

(should handle variable depths of path)
This User Gave Thanks to CarloM For This Post:
 

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BASENAME(3)						   BSD Library Functions Manual 					       BASENAME(3)

NAME
basename -- extract the base portion of a pathname SYNOPSIS
#include <libgen.h> char * basename(char *path); DESCRIPTION
The basename() function returns the last component from the pathname pointed to by path, deleting any trailing '/' characters. If path con- sists entirely of '/' characters, a pointer to the string "/" is returned. If path is a null pointer or the empty string, a pointer to the string "." is returned. RETURN VALUES
On successful completion, basename() returns a pointer to the last component of path. If basename() fails, a null pointer is returned and the global variable errno is set to indicate the error. ERRORS
The following error codes may be set in errno: [ENAMETOOLONG] The path component to be returned was larger than MAXPATHLEN. WARNINGS
The basename() function returns a pointer to internal static storage space that will be overwritten by subsequent calls. The function may modify the string pointed to by path. LEGACY SYNOPSIS
#include <libgen.h> char * basename(const char *path); In legacy mode, path will not be changed. SEE ALSO
basename(1), dirname(1), dirname(3), compat(5) STANDARDS
The basename() function conforms to X/Open Portability Guide Issue 4, Version 2 (``XPG4.2''). HISTORY
The basename() function first appeared in OpenBSD 2.2 and FreeBSD 4.2. AUTHORS
Todd C. Miller <Todd.Miller@courtesan.com> BSD
August 17, 1997 BSD
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