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Full Discussion: print out missing files in a sequence
Top Forums Shell Programming and Scripting print out missing files in a sequence Post 302616397 by Scrutinizer on Saturday 31st of March 2012 04:10:51 AM
Old 03-31-2012
Alternatively try this less general approach:
Code:
printf "%s\n" *.dcm | awk -F'[-.]' '$3>p+1{for(i=p+1;i<$3;i++){s=$0; sub($3"."$4,sprintf("%04d",i)"."$4,s); print s}}{p=$3}'

This assumes that all files have a fixed length, zero-padded counter in the third field, that they have an extension in the fourth field and that all fields (and field separators) other than the third field are identical. This also ensures wildcard expansion is in the right order..
Last edited by Scrutinizer; 03-31-2012 at 05:31 AM..
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LEARN ABOUT DEBIAN

gdcmdiff

gdcmdiff(1)							       GDCM							       gdcmdiff(1)

NAME

       gdcmdiff - .SH "SYNOPSIS"

       gdcmdiff [options] file1 file2

DESCRIPTION

       The gdcmdiff command line program takes as input two DICOM file: file1 and file2.

PARAMETERS

       file1   DICOM input filename

       file2  DICOM output filename

options
   options
	 -m	 --meta 	 Compare metainformation. Default is off.
	 -t <n>  --truncate <n>  String values trimmed to n characters.

   general options
	 -h   --help
		print this help text and exit

	 -v   --version
		print version information and exit

	 -V   --verbose
		verbose mode (warning+error).

	 -W   --warning
		warning mode, print warning information

	 -E   --error
		error mode, print error information

	 -D   --debug
		debug mode, print debug information

Simple usage
       gdcmdiff is a great tool to diff DICOM files. Usage is simply:

       $ gdcmdiff input1.dcm input2.dcm

SEE ALSO

       gdcmdump(1), gdcminfo(1)

COPYRIGHT

       Copyright (c) 2006-2011 Mathieu Malaterre

Version 2.2.0							  Tue Feb 5 2013						       gdcmdiff(1)
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