Deleting columns passed as arguments to the script
Hi all,
I am trying to delete columns in a file using a script. The columns that need to be deleted are passed as arguments to the script.
The script should look like this
The contents of the file_name.txt will be like
On running the script with the following arguments
the output should look like
I wrote the following script which works with as mentioned
The issue is that the person who is using this script doesn't have
option to cut command. So this script is not useful.
I have tried to explore other options like awk and couldn't actually get much headway.
Please help me in resolving this issue.
Also I am at a very beginner level in bash scripting and trying to learn. So any suggestions to improve the code that I wrote(with --complement option) would be appreciated.
P.S. As an initial try using awk, I tried to split the input file into columns using nothing as field seperator like
but the version of awk that I have isn't interpreting it correctly.(I know it is pretty much screwed up if I have old versions of commands without features . But what to do. Our IT team isn't willing to update to latest linux )
hi
i have a function
abc
{
//from this function i am passing args to antoher function like
def a b c j k l
}
now i want to count the no of args coming to def() function and iterate over those values
is there any way to do this one
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I want to be able to delete columns whose data have more than 10 percent of NAs.
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2 NA 2 2
1 2 1 NA
1 2 1 NA
NA 2 1 NA
1 2 1 NA
1 2 1 NA
1 2 1 NA
1 2 1 NA
1 2 1 NA
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A,5,6,,10,,
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