I used this code to strip-off $-symbol from string values.
Code:
a="$980"
b="897"
a=`echo "$a" | sed 's/$/ /g'`
b=`echo "$b" | sed 's/$/ /g'`
echo "$a"
echo "$b"
but this results in the output:
80 and 897
it works when i use
Code:
a='$987'
b='890'
But I cannot use single-quotes in my actual code as the variable values are extracted as strings and are not constant.
Is there any other command or any fix for this ?
I even used 'tr', even that works similar to sed .
Try the way Scrutinizer suggested.
The reason behind for sed cmd not working is,
$ - has special meaning in sed( almost in all regex). so you have to put \ before using the special meaning characters.
Hi,
How to strip a portion of a file name from behind...Say for Eg..i have a file name like aaaaa.bbbbb.Mar-17-2007
i want to remove .Mar-17-2007...is there a one line command which can give this output...
Thanks
Kumar (5 Replies)
Hi there, if i have some strings ie
test_324423
test_242332
test_767667
but I only want the number part (the bolded bit) how do I strip the leftmost 5 characters from the output so that i will have just
324423
242332
767667
any help would be greatly appreciated
Gary (5 Replies)
Hi ,
i have to strip the spaces in the string which has the following value
ABC DEF
i want this to appear like this
ABC DEF
is there any spilt method?
please help....
Thanks (3 Replies)
I am trying to strip out certain characters from a string on both (left & right) sides. For example, line=see@hear|touch, i only want to echo the "hear" part. Well i have tried this approach:
line=see@hear|touch
templine=${line#*@} #removed "see@"
echo ${templine%%\|*} #removed... (4 Replies)
Hi all,
I'm trying to generate a series of txt files starting from a plain csv file
part of my code:
#!/bin/ksh
INSTALLDIR=/Users/ME/Installdir
CSV=CSV.csv
TMP=/tmp/$(basename $0).txt
tr -s "\r" "\n" < /$INSTALLDIR/$CSV > $TMP
function Makefiles
{
printf '%24s:%30s\n' "sometext"... (1 Reply)
i want to parse a string and only display the digits in that string... How would i accomplish this with sed command.
For example.
input string: " 033434343 dafasdf"
output string: 03343434
Thanks (2 Replies)
Hi,
I am trying to enable rexec to automate certain tasks(it has to be rexec, not ssh or any other due to the system environment), so after switching to linux, I followed the certain instructions that were laid out in the web.
My operating system is fedora 17, so I first installed the... (1 Reply)
Hi There,
---------
file1
-------
~c asd@ac.com
--------------
Now i am using below command
cat file1|mailx -s " testing" -r " My Name" abc@tech.com (3 Replies)
I'm using an Ubuntu machine and expansion is not working properly. What would cause this? Do I need to check for any particular bash packages?
$ ipcs -m | grep $USER | awk '{printf "%s ",$2}'
$ ipcs -m | grep UNF | awk '{printf "%s ",$2}'
294912 1048577 425986 688131 786436 1245189... (14 Replies)
Discussion started by: cokedude
14 Replies
LEARN ABOUT NETBSD
dbsym
DBSYM(8) BSD System Manager's Manual DBSYM(8)NAME
dbsym -- copy kernel symbol table into db_symtab space
SYNOPSIS
dbsym [-v] [-b bfdname] kernel
DESCRIPTION
dbsym is used to copy the symbol table in a newly linked kernel into the db_symtab array (in the data section) so that the ddb(4) kernel
debugger can find the symbols. This program is only used on systems for which the boot program does not load the symbol table into memory
with the kernel. The space for these symbols is reserved in the data segment using a config option like:
options SYMTAB_SPACE=72000
The size of the db_symtab array (the value of SYMTAB_SPACE) must be at least as large as the kernel symbol table. If insufficient space is
reserved, dbsym will refuse to copy the symbol table.
To recognize kernel executable format, the -b flag specifies BFD name of kernel.
If the -v flag is given, dbsym will print out status information as it is copying the symbol table.
Note that debugging symbols are not useful to the ddb(4) kernel debugger, so to minimize the size of the kernel, one should either compile
the kernel without debugging symbols (no -g flag) or use the strip(1) command to strip debugging symbols from the kernel before dbsym is used
to copy the symbol table. The command
strip -d netbsd
will strip out debugging symbols.
SEE ALSO strip(1), ddb(4)BSD November 9, 2001 BSD
03-29-2012
