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Top Forums Shell Programming and Scripting Using arrays in bash using strings to bash built-in true Post 302615029 by kristinu on Thursday 29th of March 2012 07:03:56 AM
Old 03-29-2012
I thought it was ok, however corona suggested it is not the way to do things. Just assign default in the beginning and then if the user chooses the option overwrite it. He also suggested that checking should be done on the value string directly. If it is not set, then the option was not used.

I think I need to put a full example as things are very complicated.

---------- Post updated at 06:03 AM ---------- Previous update was at 05:19 AM ----------

Quote:
Originally Posted by Corona688
BASH doesn't have boolean types. The existence of a program named 'true' doesn't change this.

BASH doesn't have associative arrays, either. You can't use words as array indexes.
The following code did work, returning

Code:
hasArgument[mytest0] set to 0
hasArgument[mytest1] set to 1

Code:
declare -A hasArgument

hasArgument[mytest0]=false
hasArgument[mytest1]=true

if ! ${hasArgument[mytest0]}; then
  echo "hasArgument[mytest0] set to 0"
fi

if ${hasArgument[mytest1]}; then
  echo "hasArgument[mytest1] set to 1"
fi


Last edited by kristinu; 03-29-2012 at 07:26 AM..
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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