1. Shell Programming and Scripting

In a Case switch, how to ignore case sensitive in the test: e.g. case "$field" in "TEST) action1;; *) action2;; esac How to go in action1 in case of $field = TEST , or Test , or test or .... without enumerating all possibilities... Thanks,... (1 Reply)

2. UNIX for Dummies Questions & Answers

egrep -A 7 -m 2 -h 'Date:|Time:' *.html this is showing only 2 line after the context of the 2nd found match. Is this a bug in grep? egrep -A 7 -m 2 -h 'Time:' *.html - this works correctly (2 Replies)

3. Shell Programming and Scripting

Hi, In below code, i am expecting the output has Bye Bye But i am getting has Bye Hi Code: #!/usr/bin/bash var="Hi" cat txt.txt | while read var1 do next="Bye" case $var in Hi) (1 Reply)

4. Shell Programming and Scripting

Hi Experts team, i wish to use switch case in unix. my req is case $code in 1111) echo "1111" 1112) echo "1112" *) echo "default" esac see eventhough for particular case 1111 , it is always execute the default statement *), if i code like this. How can handle... (2 Replies)

5. Shell Programming and Scripting

can anyone post a sample code for a switch case in shell (1 Reply)

6. Shell Programming and Scripting

I started writing a script to save the files from a camera I got the other day, which mounts in /Volumes , and I got into it and started building this menu. The only problem is that the switch case is coming up as a syntax error at the parenthesis after a case. Here is the code: while : do ... (2 Replies)

7. Shell Programming and Scripting

case "$inputs" in sapte) find /pools/home_unix/sapte/work/models/model -name "*.xml" exec rm -i {} \;; ckm1) find /pools/home_unix/ckm1/work/models/model -name "*.xml" exec rm -i {} \;; I am getting error like as below. ./menu1.sh: line 144: syntax error near unexpected token `)'... (4 Replies)

8. Programming

Hi Am pretty new to C.. Am trying to pass the arguments from command line and use them in switch case statement.. i have tried the following #include <stdlib.h> main(int argc, char* argv) { int num=0; if ( argc == 2 ) num = argv; printf("%d is the num value",num); switch ( num ) ... (2 Replies)

9. Shell Programming and Scripting

Hi there, I'm trying to run a simple script,but i'm always getting this error Syntax error: word unexpected (expecting "in")I have searched many sites,like this,but i dont get it,it looks good so far,but wont work,maybe someone can help me. Here is the Script #!/bin/bash while : do... (6 Replies)