Hi ,
I am relatively new to unix...
Can u pls help me out to find out if the first day of the month is a working day ie from (Monday to Friday)...using Date and If clause in Korn shell..
This is very urgent.
Thanks for ur help... (7 Replies)
Hello guys it´s a pleasure to type with the unix community...I´m new in shell script and I need to insert into a #!/ksh a statment that will check if a file that I´ll receive from another script is arriving in the first working day of each month:
let´s say that I´ll reveive the following files... (1 Reply)
Within a ksh script on HP-UX I trying to calculate a percentage of a number (number/100 x percentage) using the below method and expr.
TARPERC=`expr 16 / 100 \* 5`
TARSUM=`expr 16 + $TARPERC`
ZIPSUM=`expr $TARSUM \* 2`
If the input is 16
outputs are:
TARPERC: 0
TARSUM: 16
ZIPSUM: 32... (6 Replies)
Let me preface by saying, I have looked through many threads that deal with keep the decimal, however I'm not sure that any one resolution meets my needs, ok, ok, they could. So maybe it's just that I am not understanding the resolution - therefore I am posting a new thread.
myknowledgebase=at... (2 Replies)
I need a script to figure out if a user's last login was 90 days or older. OS=AIX 5.3, shell=Korn
Here's what I have so far:
====
#!/usr/bin/ksh
NOW=`lsuser -a time_last_login root | awk -F= '{ print $2 }'`
(( LAST_LOGIN_TIME = 0 ))
(( DIFF = $NOW - $LAST_LOGIN_TIME ))
lsuser -a... (3 Replies)
Hi Guys,
I was working some time ago n was in need to calculate date 30/31 days from today including Feb (Leap yr stuff). Today date is variable depending on day of execution of script. I tried searching but was not able to get exactly what I needed....So at that I time I implemented by my own... (3 Replies)
Does anyone know how to calculate a calendar date since Jan 1, 2000 (this is day 1). I am using CSH with a Solaris system (no GNU products installed).
Example:
Input from the user (number of days):
4444
Output (dd mmm yy)
02 mar 12
---------- Post updated at 09:40 PM ----------... (9 Replies)
I wrote the day calculator also in bash. I would like to now, that is it good so?
#!/bin/bash
datum1=`date -d "1991/1/1" "+%s"`
datum2=`date "+%s"`
diff=$(($datum2-$datum1))
days=$(($diff/(60*60*24)))
echo $days
Thanks in advance for your help! (3 Replies)
Hi guys i need advice on the approach to this one......
I have a file say called
Thisfile.20130524.txt
i need to work out from the date 20130524 what day of the week that was and then process the file in 3 working days. (so not counting saturday or sunday....(will not worry about bank... (2 Replies)
Requirement is to list the files older than 365 days from multiple directories and delete them and log the list of files which are deleted to a log file.
so 1 script should only list files older than 365 days for each directory separately to a folder
The other script should read these files... (7 Replies)
Discussion started by: prasadn
7 Replies
LEARN ABOUT REDHAT
time::local
Time::Local(3pm) Perl Programmers Reference Guide Time::Local(3pm)NAME
Time::Local - efficiently compute time from local and GMT time
SYNOPSIS
$time = timelocal($sec,$min,$hour,$mday,$mon,$year);
$time = timegm($sec,$min,$hour,$mday,$mon,$year);
DESCRIPTION
These routines are the inverse of built-in perl functions localtime() and gmtime(). They accept a date as a six-element array, and return
the corresponding time(2) value in seconds since the Epoch (Midnight, January 1, 1970). This value can be positive or negative.
It is worth drawing particular attention to the expected ranges for the values provided. The value for the day of the month is the actual
day (ie 1..31), while the month is the number of months since January (0..11). This is consistent with the values returned from local-
time() and gmtime().
The timelocal() and timegm() functions perform range checking on the input $sec, $min, $hour, $mday, and $mon values by default. If you'd
rather they didn't, you can explicitly import the timelocal_nocheck() and timegm_nocheck() functions.
use Time::Local 'timelocal_nocheck';
{
# The 365th day of 1999
print scalar localtime timelocal_nocheck 0,0,0,365,0,99;
# The twenty thousandth day since 1970
print scalar localtime timelocal_nocheck 0,0,0,20000,0,70;
# And even the 10,000,000th second since 1999!
print scalar localtime timelocal_nocheck 10000000,0,0,1,0,99;
}
Your mileage may vary when trying these with minutes and hours, and it doesn't work at all for months.
Strictly speaking, the year should also be specified in a form consistent with localtime(), i.e. the offset from 1900. In order to make
the interpretation of the year easier for humans, however, who are more accustomed to seeing years as two-digit or four-digit values, the
following conventions are followed:
o Years greater than 999 are interpreted as being the actual year, rather than the offset from 1900. Thus, 1963 would indicate the year
Martin Luther King won the Nobel prize, not the year 2863.
o Years in the range 100..999 are interpreted as offset from 1900, so that 112 indicates 2012. This rule also applies to years less than
zero (but see note below regarding date range).
o Years in the range 0..99 are interpreted as shorthand for years in the rolling "current century," defined as 50 years on either side of
the current year. Thus, today, in 1999, 0 would refer to 2000, and 45 to 2045, but 55 would refer to 1955. Twenty years from now, 55
would instead refer to 2055. This is messy, but matches the way people currently think about two digit dates. Whenever possible, use
an absolute four digit year instead.
The scheme above allows interpretation of a wide range of dates, particularly if 4-digit years are used.
Please note, however, that the range of dates that can be actually be handled depends on the size of an integer (time_t) on a given plat-
form. Currently, this is 32 bits for most systems, yielding an approximate range from Dec 1901 to Jan 2038.
Both timelocal() and timegm() croak if given dates outside the supported range.
IMPLEMENTATION
These routines are quite efficient and yet are always guaranteed to agree with localtime() and gmtime(). We manage this by caching the
start times of any months we've seen before. If we know the start time of the month, we can always calculate any time within the month.
The start times are calculated using a mathematical formula. Unlike other algorithms that do multiple calls to gmtime().
timelocal() is implemented using the same cache. We just assume that we're translating a GMT time, and then fudge it when we're done for
the timezone and daylight savings arguments. Note that the timezone is evaluated for each date because countries occasionally change their
official timezones. Assuming that localtime() corrects for these changes, this routine will also be correct.
BUGS
The whole scheme for interpreting two-digit years can be considered a bug.
The proclivity to croak() is probably a bug.
perl v5.8.0 2002-06-01 Time::Local(3pm)