Hi All,
I got a script from one of the unix forums for reporting on filesystem usage and wanted to use it but it keeps giving me the following error.
0403-057 Syntax error at line 70
The script is shown below.
Pls help as I am new to UNIX.
# set -x
# D I S K S P A C E . S H
#
#... (2 Replies)
Can someone please tell me wht is wrong with the following peice of code?
I keep getting the following error -
0403-057 Syntax error at line 52 : `)' is not expected.
case "${option_count}" in
1) java -Xms256m -Xmx1536m "${APPLNAME}" "${ACTION_TYPE}" > "${LOGFILE}" 2>... (2 Replies)
Hi All
I am quite new to Unix. Following is a shell script that i have written and getting the subject mentioned error.
#!/bin/ksh
#-------------------------------------------------------------------------
# File: ang_stdnld.ksh
#
# Desc: UNIX shell script to extract Store information.... (3 Replies)
I am getting the error :
rocfm/wls_subload/in/processed_files/tel_input_additional_checked_all_mandatory.txt: 0403-057 Syntax error at
line 1 : `|' is not expected.
>>>>ALL MANDATORY FIELDS CHECKING IS SUCCESSFUL count is 0
... (3 Replies)
i dont know where m i mistaking.. please help me out with this issue :(
thanks in advance:rolleyes:
one_main()
{
a=100
while ;
do
clear
echo "##############################################"
echo ":: CURRENTLY YOU ARE IN RC AND OC MARKING ::"
echo... (1 Reply)
Hi,
I am new to shell scripting.i am trying to mail after my backup completed.
Here is my shell script:
if ; then
egrep (ERROR|error|Error|RMAN-) ${/backup/RMANBKUP/spool/shelltest.log} > /dev/null
if ; then
RESULT_MSG=WARNING: Errors occurred during the ${ORACLE_SID} Rman... (3 Replies)
I am getting the following error when I am running a script in ksh when trying to execute an if statement comparing two numerical values
tstmb.sh: 1.5321e+08: 0403-057 Syntax error
Below is my code snippet.
#!/bin/ksh
set -x
TODAY=$(date +%y%m%d)
for file in $(ls -rt *.log | tail... (11 Replies)
Hi,
While executing my code i am getting below Error:
./check_disk1: 0403-057 Syntax error at line 55 : `(' is not expected.
My code is :
#!/bin/ksh
PROGNAME=`basename $0`
STATE_OK=0
STATE_WARNING=1
STATE_CRITICAL=2
STATE_UNKNOWN=3
OS=$(uname)
AWK="/usr/bin/awk"... (6 Replies)
Hi Everyone,
I am getting strange behavior, same script runs fine without any error in one AIX machine, whereas on another it is throwing this error "0403-057 Syntax error at line 399 : `"' is not matched", I also ran the script in debug mode.
This is the output, still doesn't say anything.... (2 Replies)
Discussion started by: sid1987
2 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)