I have tested and tried to edit my script with yout advice.. but still unable to get the value of PWD to replace my copy of shell script.
I have 2 shell script, a.sh and b.sh.
a.sh will make a copy of b.sh at /etc/init.d and will replace the "$PWD" keyword in the copy of b.sh.
Below is the edited code for my scripts:
a.sh
b.sh
when i execute the a.sh... the keyword PWD in copy of b.sh is replaced with the string "$current_dir"
and eventually i have this
current_dir=""$current_dir""
in my copyOf b.sh....
I tried to manipulate the quotes.. but still unable to get the thing right...
Hi there. If variables are named inside of a ksh script, how is it possible to pass these to sed?
The affected portion of my script goes something like this:
A=`cut -d. -f1 $FILE`
B=`cut -d. -f2 $FILE`
C=`cut -d. -f3 $FILE`
sed 's/1111/$A/g;s/2222/$B/g;s/3333/$C/g' file > anotherfile
... (2 Replies)
Hi, Thanks for looking,,,,
(kornshell)
tmp3 is a list of line numbers
I want to print the lines from my list
code:
while read j
do
echo $j #works fine
echo $filename #works fine
#sed "'$jp'" "$filename" ... (7 Replies)
Hello,
I'd like to pass a variable to a sed command in a perl script. The script is like this :
#!/usr/bin/perl -w
$newline="new";
system q(sed '/insert/ i\ '$newline <sed1.txt >sed2.txt);
But the interpretor wouldn't recognize $newline, it inserts a "\n" instead.
I've also... (4 Replies)
hi all
is possible to pass shell (bash) variable to sed like it is in awk?
example:
awk script is storred in awk.awk file and I am passing variable called var to this file.
$ cat awk.awk
{if ($5==var) print $0}
so it works when i issue
$ bash_var=24
$ ls -l | awk -v... (1 Reply)
Ok, so, let's say I have the variable $GMAILID....How can I use it with sed command so to replace a string in a file? e.g.:
sed -i 's/$GMAILID/test@gmail.com/' /home/$USER/Desktop/sendmail (4 Replies)
Hi,
I am trying to replace the value of a variable in a file through another script.
Example:
Filename : abc.txt contents:
a=10
b=20
c=30
Need to change the value of, say, b - Tried using the following:
sed "s/${b}/15/g" abc.txt
Have tried various forms of sed (with single quotes,... (4 Replies)
I have a file having some text like:
PATH_ABC=/user/myLocation
I have to replace "/user/myLocation" with a session variable say, $REPLACE_PATH,
where $REPLACE_PATH=/user/myReplaceLocation
The following sed command is not working. It is writing PATH_ABC=$REPLACE_PATH in the file
... (2 Replies)
I'm trying to create a ksh script that will ask the user for the port number. $PORT1 is the variable I want to use that will contain whatever numbers the user inputs. The script would edit ports.txt file, search and delete "./serv 110.1.0.1.$PORT1 200;=3" .
So if the user types 50243 then the... (5 Replies)
I want to make a config file which contain all the paths.
i want to read the config file line by line and pass as an argument on my below function.
Replace all the path with reading config path line by line and pass in respective functions.
how can i achieve that?
Kindly guide.
... (6 Replies)
Hi All
I have one file with multiple lines in it, each line has static text and some variable enclosed in <<filename>> as well. e.g. as below
123, <<file1.txt>> this is my name, I stay at <<city.txt>> Thanks for visiting
348384y, this is my name <<fileabc.txt>>, I stay at near the mall of... (8 Replies)
Discussion started by: reldb
8 Replies
LEARN ABOUT OSX
pwd
PWD(1) BSD General Commands Manual PWD(1)NAME
pwd -- return working directory name
SYNOPSIS
pwd [-L | -P]
DESCRIPTION
The pwd utility writes the absolute pathname of the current working directory to the standard output.
Some shells may provide a builtin pwd command which is similar or identical to this utility. Consult the builtin(1) manual page.
The options are as follows:
-L Display the logical current working directory.
-P Display the physical current working directory (all symbolic links resolved).
If no options are specified, the -L option is assumed.
ENVIRONMENT
Environment variables used by pwd:
PWD Logical current working directory.
EXIT STATUS
The pwd utility exits 0 on success, and >0 if an error occurs.
SEE ALSO builtin(1), cd(1), csh(1), sh(1), getcwd(3)STANDARDS
The pwd utility conforms to IEEE Std 1003.1-2001 (``POSIX.1'').
BUGS
In csh(1) the command dirs is always faster because it is built into that shell. However, it can give a different answer in the rare case
that the current directory or a containing directory was moved after the shell descended into it.
The -L option does not work unless the PWD environment variable is exported by the shell.
BSD April 12, 2003 BSD