How to pass value of pwd as variable in SED to replace variable in a script file Post: 302613615

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LEARN ABOUT FREEBSD

pwd

PWD(1)							    BSD General Commands Manual 						    PWD(1)

NAME

     pwd -- return working directory name

SYNOPSIS

     pwd [-L | -P]

DESCRIPTION

     The pwd utility writes the absolute pathname of the current working directory to the standard output.

     Some shells may provide a builtin pwd command which is similar or identical to this utility.  Consult the builtin(1) manual page.

     The options are as follows:

     -L      Display the logical current working directory.

     -P      Display the physical current working directory (all symbolic links resolved).

     If no options are specified, the -P option is assumed.

ENVIRONMENT

     Environment variables used by pwd:

     PWD  Logical current working directory.

EXIT STATUS

     The pwd utility exits 0 on success, and >0 if an error occurs.

SEE ALSO

     builtin(1), cd(1), csh(1), sh(1), getcwd(3)

STANDARDS

     The pwd utility conforms to IEEE Std 1003.1-2001 (``POSIX.1'').

BUGS

     In csh(1) the command dirs is always faster because it is built into that shell.  However, it can give a different answer in the rare case
     that the current directory or a containing directory was moved after the shell descended into it.

     The -L option does not work unless the PWD environment variable is exported by the shell.

BSD
								  April 12, 2003							       BSD

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pass a variable to sed p in a loop?

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Pass perl variable to sed

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pass variable to sed like in awk (-v switch)

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Replace value of a variable in a file through script using sed

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How to replace a string with a variable in a file using sed?

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