I came across this script online to convert Epoch time to proper date format, but I am receiving the following error
Also, I have HISTTIMEFORMAT set in user's .profile so that their history output shows time stamps. Additionally I have changed their .history location to a dedicated directory in /var/log. Example as below:
[root@H99A100 user_history]# ./test
Month '23' out of range 0..11 at -e line 2
This is the script I am using:
Code:
#!/bin/bash
# YYYY MM DD HH MM SS
# perl autosplits the string and uses timelocal to return
# the number of seconds from the Epoch
# No error checking!
function seconds_from_epoch {
echo $*| perl -MTime::Local -ane '
my $epochseconds = timelocal($F[5], $F[4], $F[3], $F[2], $F[1], $F[0]);
print "$epochseconds\n"; '
}
# parse file s32adm_bash_history date and time
set - $(ls -l s32adm_bash_history)
fdate=$6
ftime=$7
# parse the year, month, and day
set - $(IFS="-"; echo $fdate)
fyear=$1
fmonth=$2
fday=$3
# parse the hours and minutes
set - $(IFS=":"; echo $ftime)
fhour=$1
fmin=$2
totsecs=$(seconds_from_epoch "$fyear $fmonth $fday $fhour $fmin 0")
echo $totsecs
Can someone please point out what I am doing wrong?
Is there an easy method to do an on the fly conversion of a standard epoch time (seconds from 1970) to more readable date format?
Does Unix have anything built in to do this? (4 Replies)
hello gurus,
i want a perl/shell script which once invoked should convert a set of EPOCH timestamps to local time ( IST..i want) .
how does it work ,i have an idea on that..but writing a perl/shell script for it is not possible for me...so i need help for the same.
my exact requirement is... (2 Replies)
how can I get the current standard epoch time (seconds from 1970) in a shell script?
I know I could do this with a bit of perl of even c++ but i want to do it in Bourne shell..... (14 Replies)
I need to convert an epoch time from a file into a standard UTC time and output it in the same format but I'm not sure what's the best approach
here's the input file and the bold part is what I need to convert.
1,1,"sys1",60,300000
2,"E:",286511144960
3,1251194521,"E:",0,0... (2 Replies)
I need shell or Perl script to get the epoch time automatically
Example I need to execute mysql command to delete content less then given epoch time
If date is 01-07-2010 (dd-mm-yy) epoch should be lees 7 days mean 23-06-2010 for 23-06-2010 I need epoch time
Delete BS_table where... (1 Reply)
Dear experts,
I have an epoch time input file such as : -
1302451209564
1302483698948
1302485231072
1302490805383
1302519244700
1302492787481
1302505299145
1302506557022
1302532112140
1302501033105
1302511536485
1302512669550
I need the epoch time above to be converted into real... (4 Replies)
I am trying get time difference of two dates in secs. Initially I want to convert a standard date format to epoch for two dates and then subtract the two epoch dates.
Example :
date -d "2007-09-01 17:30:40" '+%s'
But this gives me below error
date: illegal option -- d
Usage: date
OS: AIX... (6 Replies)
Hi All,
Please read the below data carefully.
I need an unix command for converting unix timestamp to Epoch timestamp.
I need to daily convert this today's unix(UTC) time to epoch time, so i am thinking to make a shellscript for this.
Please help me for this by providing... (3 Replies)
Hi there
I'm using this script to convert command line history with Epoch time stamp to human readable. While it works fine with users with /bin/csh shell, it fails to convert for users with /bin/bash shell. Why is this happening? I even changed and added * and after the # but it still didnt... (2 Replies)
Hi. I have timestamps that I am trying to convert to epoch time. An example:
I am trying to convert this to an epoch timestamp but have one little glitch. I have this:
import time
date_time = ''
pattern = ''
epoch = int(time.mktime(time.strptime(date_time, pattern)))
print epoch... (1 Reply)
Discussion started by: treesloth
1 Replies
LEARN ABOUT DEBIAN
datetime::format::epoch::dotnet
DateTime::Format::Epoch::DotNet(3pm) User Contributed Perl Documentation DateTime::Format::Epoch::DotNet(3pm)NAME
DateTime::Format::Epoch::DotNet - Convert DateTimes to/from .NET epoch seconds
SYNOPSIS
use DateTime::Format::Epoch::DotNet;
my $dt = DateTime::Format::Epoch::DotNet->parse_datetime( 1051488000 );
DateTime::Format::Epoch::DotNet->format_datetime($dt);
# 1051488000
my $formatter = DateTime::Format::Epoch::DotNet->new();
my $dt2 = $formatter->parse_datetime( 1051488000 );
$formatter->format_datetime($dt2);
DESCRIPTION
This module can convert a DateTime object (or any object that can be converted to a DateTime object) to the number of seconds since the
epoch defined in the .NET Framework SDK.
Note that this epoch is defined in the local time zone. This means that these two pieces of code will print the same number of seconds,
even though they represent two datetimes 6 hours apart:
$dt = DateTime->new( year => 2003, month => 5, day => 2,
time_zone => 'Europe/Amsterdam' );
print $formatter->format_datetime($dt);
$dt = DateTime->new( year => 2003, month => 5, day => 2,
time_zone => 'America/Chicago' );
print $formatter->format_datetime($dt);
METHODS
Most of the methods are the same as those in DateTime::Format::Epoch. The only difference is the constructor.
o new()
Constructor of the formatter/parser object. It has no parameters.
SUPPORT
Support for this module is provided via the datetime@perl.org email list. See http://lists.perl.org/ for more details.
AUTHOR
Eugene van der Pijll <pijll@gmx.net>
COPYRIGHT
Copyright (c) 2003 Eugene van der Pijll. All rights reserved. This program is free software; you can redistribute it and/or modify it
under the same terms as Perl itself.
SEE ALSO
DateTime
datetime@perl.org mailing list
perl v5.10.1 2007-12-03 DateTime::Format::Epoch::DotNet(3pm)