Reformatting data in matrix form Post: 302609823

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Top Forums Shell Programming and Scripting Reformatting data in matrix form Post 302609823 by Corona688 on Tuesday 20th of March 2012 12:57:30 PM

03-20-2012

Registered User

I have a way to do this, but it will need to be told what the columns are, since it can't go backwards and insert the first line after it's collated everything.

Code:

$ cat rotarr.awk

BEGIN {
        if(!COLS)       COLS="|A|B|C|D"

        split(COLS, C, "|");
        for(N=2; C[N]; N++)     printf("\t%s", C[N]);
        printf("\n");
}

!LASTROW { LASTROW=$2 }

$2 != LASTROW {
        printf("%s", LASTROW);
        for(N=2; C[N]; N++)
        {
                if(!DATA[C[N]]) DATA[C[N]]=DEF;
                printf("\t%s", DATA[C[N]]);
        }

        printf("\n");
        for(X in DATA)  delete DATA[X];
        LASTROW=$2
}

{
        DATA[$1]=$4
        DEF=$3
}

END {
        printf("%s", LASTROW);
        for(N=2; C[N]; N++)
        {
                if(!DATA[C[N]]) DATA[C[N]]=DEF;
                printf("\t%s", DATA[C[N]]);
        }

        printf("\n");
        for(X in DATA)  delete DATA[X];
}

$ awk -v COLS="|A|B|C|D" -f rotarr.awk data

        A       B       C       D
pos1    2       3       4       5
pos2    6       7       9       8
pos3    7       9       7       7

$

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sppequ

SPPEQU(l)								 )								 SPPEQU(l)

NAME

       SPPEQU  -  compute  row and column scalings intended to equilibrate a symmetric positive definite matrix A in packed storage and reduce its
       condition number (with respect to the two-norm)

SYNOPSIS

       SUBROUTINE SPPEQU( UPLO, N, AP, S, SCOND, AMAX, INFO )

	   CHARACTER	  UPLO

	   INTEGER	  INFO, N

	   REAL 	  AMAX, SCOND

	   REAL 	  AP( * ), S( * )

PURPOSE

       SPPEQU computes row and column scalings intended to equilibrate a symmetric positive definite matrix A in packed  storage  and  reduce  its
       condition number (with respect to the two-norm). S contains the scale factors, S(i)=1/sqrt(A(i,i)), chosen so that the scaled matrix B with
       elements B(i,j)=S(i)*A(i,j)*S(j) has ones on the diagonal.  This choice of S puts the condition number of B within a factor N of the small-
       est possible condition number over all possible diagonal scalings.

ARGUMENTS

       UPLO    (input) CHARACTER*1
	       = 'U':  Upper triangle of A is stored;
	       = 'L':  Lower triangle of A is stored.

       N       (input) INTEGER
	       The order of the matrix A.  N >= 0.

       AP      (input) REAL array, dimension (N*(N+1)/2)
	       The  upper or lower triangle of the symmetric matrix A, packed columnwise in a linear array.  The j-th column of A is stored in the
	       array AP as follows: if UPLO = 'U', AP(i + (j-1)*j/2) = A(i,j) for 1<=i<=j; if UPLO = 'L', AP(i	+  (j-1)*(2n-j)/2)  =  A(i,j)  for
	       j<=i<=n.

       S       (output) REAL array, dimension (N)
	       If INFO = 0, S contains the scale factors for A.

       SCOND   (output) REAL
	       If  INFO = 0, S contains the ratio of the smallest S(i) to the largest S(i).  If SCOND >= 0.1 and AMAX is neither too large nor too
	       small, it is not worth scaling by S.

       AMAX    (output) REAL
	       Absolute value of largest matrix element.  If AMAX is very close to overflow or very close  to  underflow,  the	matrix	should	be
	       scaled.

       INFO    (output) INTEGER
	       = 0:  successful exit
	       < 0:  if INFO = -i, the i-th argument had an illegal value
	       > 0:  if INFO = i, the i-th diagonal element is nonpositive.

LAPACK version 3.0						   15 June 2000 							 SPPEQU(l)