I would like my csh prompt to behave like the linux csh prompt setting done by linux command (set prompt="%n@%m %c]$ ")
how do I do that?
What I'm trying to do is that I would like to see what directory I'm in by looking at the prompt.
I've figured out that %n is like $user, and %m is like... (3 Replies)
Is it possibe to use sed for the following? I would like to truncate the output of a directory path if it's over 3 directory levels deep. For example:
/dir1/dir2/dir3 -- NO change required
but,
/dir1/dir2/dir3/dir4 would output as ~/dir4
Thanks. (4 Replies)
If I the path to a directory, what command can I use to return the actual name of that directory.
test=`pwd`/folder1
> $test
folder1
I'd rather avoid anything with regular expressions. Any ideas? (1 Reply)
Hi,
I have a file abcd.txt which has contents in the form of full path file names i.e.
$home> vi abcd.txt
/a/b/c/r1.txt
/q/w/e/r2.txt
/z/x/c/r3.txt
Now I want to retrieve only the directory path name for each row
i.e
/a/b/c/
/q/w/e/
How to get the same through shell script?... (7 Replies)
If I enter (simplified):
find . -printf "%p\n"
then all files in the output are prepended by a "." like
./local/share/test23.log
How can achieve that
a.) the leading "./" is omitted
and/or
b.) the full path to the current directory is inserted (enclosed by brackets and a blank)... (1 Reply)
HI Guys,
I am truing to add some directories to the productive HP-UX (like /usr/sbin)
the problem is that i tried some methods like (export) and setenv but i failed.
I add some logs output of the commands to provide you with more info .
the user which I am trying to add this path is different... (5 Replies)
Hello,
I am looking for a command that will give me the last directory name from a path
ex 1 :
/dir1/dir/2/dir3/
output needed
dir3
ex 2 :
/dir1/dir/2/dir3/dir4/
output needed
dir4 (1 Reply)
My input is as below :
/splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt
/splunk/scrubbed/rebate/IFIND.REBTE.WROC.txt
/splunk/scrubbed/loyal/IFIND.HELLO.WROC.txt
/splunk/scrubbed/triumph/ifind.triumph.txt
From the above input I want to extract the file names only .
Basically I want to... (5 Replies)
Hello,
I am creating a file with all the source folders included in my git branch, when i grep for the used source, i found source included as relative path instead of absolute path, how can convert relative path to absolute path without changing directory to that folder and using readlink -f ? ... (4 Replies)
What is the difference ../directory path and ./directory path in ksh? (1 Reply)
Discussion started by: TestKing
1 Replies
LEARN ABOUT DEBIAN
lib::abs
lib::abs(3pm) User Contributed Perl Documentation lib::abs(3pm)NAME
lib::abs - "lib" that makes relative path absolute to caller.
SYNOPSIS
Simple use like "use lib ...":
use lib::abs qw(./mylibs1 ../mylibs2);
use lib::abs 'mylibs';
Extended syntax (glob)
use lib::abs 'modules/*/lib';
There are also may be used helper function from lib::abs (see example/ex4):
use lib::abs;
# ...
my $path = lib::abs::path('../path/relative/to/me'); # returns absolute path
DESCRIPTION
The main reason of this library is transformate relative paths to absolute at the "BEGIN" stage, and push transformed to @INC. Relative
path basis is not the current working directory, but the location of file, where the statement is (caller file). When using common "lib",
relative paths stays relative to curernt working directory,
# For ex:
# script: /opt/scripts/my.pl
use lib::abs '../lib';
# We run `/opt/scripts/my.pl` having cwd /home/mons
# The @INC will contain '/opt/lib';
# We run `./my.pl` having cwd /opt
# The @INC will contain '/opt/lib';
# We run `../my.pl` having cwd /opt/lib
# The @INC will contain '/opt/lib';
Also this module is useful when writing tests, when you want to load strictly the module from ../lib, respecting the test file.
# t/00-test.t
use lib::abs '../lib';
Also this is useful, when you running under "mod_perl", use something like "Apache::StatINC", and your application may change working
directory. So in case of chdir "StatINC" fails to reload module if the @INC contain relative paths.
RATIONALE
Q: We already have "FindBin" and "lib", why we need this module?
A: There are several reasons:
1) "FindBin" could find path incorrectly under "mod_perl"
2) "FindBin" works relatively to executed binary instead of relatively to caller
3) Perl is linguistic language, and `use lib::abs "..."' semantically more clear and looks more beautiful than `use FindBin; use lib
"$FindBin::Bin/../lib";'
4) "FindBin" b<will> work incorrectly, if will be called not from executed binary (see <http://github.com/Mons/lib-abs-vs-findbin>
comparison for details)
BUGS
None known
COPYRIGHT & LICENSE
Copyright 2007-2010 Mons Anderson.
This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
AUTHOR
Mons Anderson, "<mons@cpan.org>"
CONTRIBUTORS
Oleg Kostyuk, "<cub@cpan.org>"
perl v5.10.1 2010-11-16 lib::abs(3pm)