My program usage takes the form for example;
$ theApp 2 "one or more words"
i.e. 3 command line arguments; application name, an integer, some text
My code includes the following 4 lines:
int anInteger;
char words;
sscanf(argv, "%d", &anInteger);
sscanf(argv, "%s", &message);
Based... (2 Replies)
I am trying to print command line arguments one per second. I have this
while
do
echo "6"
shift
echo "5"
shift
echo "4"
shift
echo "3"
shift
echo "2"
shift
echo "1"
shift
done (2 Replies)
I have this while loop and at the end I am trying to get it to tell me the last argument I entered. And with it like this all I get is the sentence with no value for $1. Now I tried moving done after the sentence and it printed the value of $1 after every number. I don't want that I just want... (2 Replies)
Hi,
I have to store all the command line arguments into an array.
I have the following code.
**********************
#! /bin/sh
set -A arr_no_updates
i=1
while
do
arr_no_updates=$($i)
echo ${arr_no_updates}
i=$(($i+1))
done**************** (1 Reply)
I have this code, I thought it would automatically know the args sent to script when called from shell. But it seems to not see any...
main script:
. args
. errors
. opt
. clean
dbfile=""
opfile=""
# calls function in script below
chkarg
#check commands (2 Replies)
Hi I am executing a KSH script by passing command line arguments
example: Red Green Dark Red Blue
when I am splitting the arguments by using " "(Space) as delimiter
But the colour Dark Red is a single parameter. But it is getting splitted in between
How to avoid this. Please help Also... (4 Replies)
Hi,
i have a perl script named test.pl. It is executed as
cat *.log|test.pl
i need the complete command line args. I tried using basename $0 but im getting test.pl only but not cat *.log...
Can anyone help me on this.
Thanks in advance (3 Replies)
Hello All,
I have a Bash Script and an Expect script that together will SSH to another server and
do some stuff there... From within the Bash Script I process the Command Line Arguments,
which are Required Args and Optional Args.
When I call the Expect script from the Bash Script, I pass... (4 Replies)
I'm using getopts to process command line args in a Bash script. The code looks like this:
while getopts ":cfmvhs:t:" option; do
case $option in
c) operationMode="CHECK"
;;
f) operationMode="FAST"
;;
m) ... (6 Replies)
Discussion started by: gencon
6 Replies
LEARN ABOUT PLAN9
setuid
SETUID(1) General Commands Manual SETUID(1)NAME
setuid - run a command with a different uid.
SYNOPSIS
setuid username|uid command [ args ]
DESCRIPTION
Setuid changes user id, then executes the specified command. Unlike some versions of su(1), this program doesn't ever ask for a password
when executed with effective uid=root. This program doesn't change the environment; it only changes the uid and then uses execvp() to find
the command in the path, and execute it. (If the command is a script, execvp() passes the command name to /bin/sh for processing.)
For example,
setuid some_user $SHELL
can be used to start a shell running as another user.
Setuid is useful inside scripts that are being run by a setuid-root user -- such as a script invoked with super, so that the script can
execute some commands using the uid of the original user, instead of root. This allows unsafe commands (such as editors and pagers) to be
used in a non-root mode inside a super script. For example, an operator with permission to modify a certain protected_file could use a
super command that simply does:
cp protected_file temp_file
setuid $ORIG_USER ${EDITOR:-/bin/vi} temp_file
cp temp_file protected_file
(Note: don't use this example directly. If the temp_file can somehow be replaced by another user, as might be the case if it's kept in a
temporary directory, there will be a race condition in the time between editing the temporary file and copying it back to the protected
file.)
AUTHOR
Will Deich
local SETUID(1)