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Top Forums Shell Programming and Scripting Need one liner to search pattern and print everything expect 6 lines from where pattern match made Post 302607786 by chidori on Thursday 15th of March 2012 10:45:27 AM
Old 03-15-2012
it works.. but..

Hi ,

It works but i am trying something like this.. and it removes the original file. why so ?
Code:
ssh $i "/usr/xpg4/bin/awk -v pat="CMDS=" -v cnt=6 '{a[NR]=$0;}END{for(i=1;i<=NR;i++){print a[i];if(a[i] ~ pat ){i=i+cnt;}}}'  sudofile > sudofilecopy"

when i check it empties sudofile content
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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