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Top Forums Shell Programming and Scripting File Reading for a certain string and echo the line before Post 302606045 by alister on Friday 9th of March 2012 11:47:09 AM
Old 03-09-2012
Quote:
Originally Posted by ctsgnb
@alister

I tried your code (on a SunOS 5.10 machine), it didn't work ( i have an output as below)
Hi, ctsgnb:

Works fine for me with a BSD sed. Also, the script should be POSIX-compliant.

If you figure out why it fails on your implementation, I'd be interested to know; I'm not familiar with your system's userland.

Regards,
Alister
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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