Is the block of code the only block that starts <?php and finishes ?>? I suspect that maybe there are other blocks that start and end this way, but on the off chance that this will be the only block like this, then this sed should work:
It deletes all lines between the starting line with "<?php" and the ending "?>" line as it reads the file. The updated file is written to $file.
If you can use this sed, just replace it in the earlier example.
If there are more than one php blocks of code, then you'll need to find a unique string inside the block that you want to delete. Change the one line in the script below that has "/enter your nickname/" to contain the unique string from the block of code and it should find and delete the lines containing the string.
Hope this helps get you going.
Last edited by agama; 03-04-2012 at 01:44 PM..
Reason: corrected comment that introduced a bug
hi guys,
Suppose you have 100 files in a folder and you want to replace all occurances of a word say "ABCD" in those files with "DCBA", how would you do
it ???
jatin (13 Replies)
I used the following script
cd pathname
for y in `ls *`;
do sed "s/ABCD/DCBA/g" $y > temp; mv temp $y;
done
and it worked fine for finding and replacing strings with names etc. in all files of the given path.
I'm trying to replace a string which consists of path (location of file)
... (2 Replies)
i have to search a string and replace with multiple lines.
example
Input
echo 'sample text'
echo 'college days'
output
echo 'sample text'
echo 'information on students'
echo 'emp number'
echo 'holidays'
i have to search a word college and replace the multiple lines
i have... (1 Reply)
I used the following script
cd pathname
for y in `ls *`;
do sed "s/ABCD/DCBA/g" $y > temp; mv temp $y;
done
and it worked fine for finding and replacing strings with names etc. in all files of the given path.
I'm trying to replace a string which consists of path (location of file)
... (11 Replies)
find . -type f -name "*.sql" -print|xargs perl -i -pe 's/pattern/replaced/g'
this is simple logic to find and replace in multiple files & folders
Hope this helps.
Thanks
Zaheer (0 Replies)
Hi,
I am creating a script to do a find and replace single/multiple lines in a file with any number of lines.
I have written a logic in a script that reads a reference file say "findrep" and populates two variables $FIND and $REPLACE
print $FIND gives
Hi How r $u
Rahul()
Note:... (0 Replies)
Can someone tell me how I can do this?
e.g:
a=$(echo -e wert trewt ertert ertert ertert erttert
erterte
rterter
tertertert
ert)
How do i replace the STRING with $a?
I try this:
sed -i 's/STRING/'"$a"'/g' filename.ext
but this don' t work (2 Replies)
I have a list of files all over a file system e.g.
/home/1/foo/bar.x
/www/sites/moose/foo.txtI'm looking for strings in these files and want to replace each occurrence with a replacement string, e.g.
if I find: '#@!^\&@ in any of the files I want to replace it with: 655#@11, etc.
There... (2 Replies)
Hello Guys,
I need to replace a string with multiple lines.
For eg:-
ABC,DEF,GHI,JKL,MNO,PQR,STU
need to convert the above as below:-
ABC,DEF,
GHI1
GHI2
GHI3,
JKL,MNO,
PQR1
PQR2
PQR3,
STU
i have tried using code as:- (2 Replies)
Discussion started by: jassi10781
2 Replies
LEARN ABOUT DEBIAN
h5unjam
h5unjam(1) General Commands Manual h5unjam(1)NAME
h5unjam - Extract the user block from a HDF5 file
SYNOPSIS
h5unjam -i in_file.h5 [-u user_block | --delete] [-o out_file.h5]
DESCRIPTION
h5unjam splits an HDF5 file, writing the user block to a file or stdout and the HDF5 file to an HDF5 file with a header at byte 0 (i.e.,
with no user block).
If out_file.h5 is given, a new file is created with the in_file.h5 without the user block. In this case, infile.h5 is unchanged.
If out_file.h5 is not specified, the user_block is removed and in_file.h5 is rewritten, starting at byte 0.
If user_block is set, the user block will be written to user_block. If user_block is not set, the user block (if any) will be written to
stdout. If --delete is selected, the user block will not be not written.
EXAMPLE USAGE
For an HDF5 file, with_ub.h5, with a user block, extract the user block to user_block.txt and the HDF5 file to wo_ub.h5.
h5unjam -i with_ub.h5 -u user_block.txt -i wo_ub.h5
RETURN VALUE
h5unjam returns the size of the output file, or -1 if an error occurs.
CAVEATS
This tool copies all the data (sequentially) in the file(s) to new offsets. For a large file, this copy will take a long time.
The most efficient way to create a user block is to create the file with a user block (see H5Pset_user_block), and write the user block
data into that space from a program.
The user block is completely opaque to the HDF5 library and to the h5jam and h5unjam tools. The user block is simply read or written as a
string of bytes, which could be text or any kind of binary data. It is up to the user to know what the contents of the user block means
and how to process it.
When the user block is extracted, all the data is written to the output, including any padding or unwritten data.
This tool moves the HDF5 file through byte copies, i.e., it does not read or interpret the HDF5 objects.
SEE ALSO h5dump(1), h5ls(1), h5diff(1), h5import(1), gif2h5(1), h52gif(1), h5perf(1), h5jam(1).
h5unjam(1)