Hi, I have a input file like this
TH2TH2867Y NOW33332106Yo You Baby
TH2TH3867Y NOW33332106No Way Out
TH2TH9867Y NOW33332106Can't find it
TJ2TJ2872N WOW33332017sure thing alas
TJ2TJ3872N WOW33332017the sky rocks
TJ2TJ4872N WOW33332017nothing else matters ... (4 Replies)
I don't necessary have a problem, as I have a solution. It is just that there may be a better solution.
GOAL: Part one: Parse data from a file using the "\" as a delimiter and extracting only the last delimiter. Part two: Parse same file and extract everything but the last delimited item.
... (8 Replies)
Hi, I am searching for a fast awk hack to eliminate from an ICS file events which have been modified at a certain time.
The structure for parsing is the following:
BEGIN:VEVENT
....
LAST-MODIFIED:...some date...
...
END:VEVENT
If the date matches for example LAST-MODIFIED:20110823 the... (2 Replies)
i am parsing te /etc/passwd file and extracting the login and names alone.
But for some entries only login exist but no name. so i dont want to display those:
how i can check non emptiness for login and name in single if statement:
#!/usr/bin/bash
while IFS=: read login a b c name e
do
... (3 Replies)
Hi,
I have a data set as shown below:
09e757fd,22727,2012-03-01,text1,text2,to
3fd0cae7,310,2012-03-01,text3,text4,to
3fd0cae7,310,2012-03-01,text3,text5,to
3fd0cae7,311,2012-03-01,text7,text10,cc
3fd0cae7,311,2012-03-01,text7,text11,to
3fd0cae7,312,2012-03-01,text8,text15,to... (3 Replies)
I've got a number of RHEL systems and I'm trying to use awk to read and format the output of /etc/passwd. But I'd like to display the host name of the system at the beginning of each line of output.
I've got it working without the adding the host name in this script:
#!/bin/bash
... (3 Replies)
Looking to parse a file to remove the duplicates and get only few fields and uniq rows.
input.tx
Loc (TC) ID : ssfad_fs
Serial : PIC002340098
... (8 Replies)
I have a command to print out the top 5 most cpu intensive commands:
ps aux --sort=-%cpu --no-headers
I would like to make a printout containing only the parsed file name.
So, I want to turn this:
$ ps aux --sort=-%cpu --no-headers
user 24883 4.3 1.7 2010436 131440 ? Sl ... (2 Replies)
Discussion started by: bedtime
2 Replies
LEARN ABOUT DEBIAN
partimaged-passwd
partimaged-passwd(8) Partition Image Server Configuration partimaged-passwd(8)NAME
partimaged-passwd - Manage partimaged user accounts
SYNTAX
partimaged-passwd [-Dhl] username password
partimaged-passwd [-Dhl] username
DESCRIPTION
partimaged can either authenticate against local user accounts (This needs access to /etc/shadow. As this is a potential security risk this
method is not recommended) or its own password database in /etc/partimaged/passwd.db. To simplify the management of the partimaged user
database this tool was written. It allows to easily add and remove users or list the users in the database. All users in this database are
allowed to access the partimaged server.
OPTIONS -D username
Delete the specified user from the password file.
-l List users in password file and exit.
-h Output help information and exit.
FILES
/etc/partimaged/passwd.db
AUTHORS
Michael Biebl <biebl@debian.org>
SEE ALSO partimaged(8), partimagedusers(5), partimage(1)Michael Biebl <biebl@teco.edu> 0.1 partimaged-passwd(8)