Sponsored Content
Top Forums Shell Programming and Scripting Passing awk variables to shell Post 302603356 by urello on Wednesday 29th of February 2012 08:35:06 PM
Old 02-29-2012
Cool, but it is not working if i use ":" as filed separator and values with spaces. How to resolve this?
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Passing Variables to AWK

Does anybody have an explanation for the following: The following scripts runs fine on IRIX64 6.5 but has bugs on Solaris 8. #! /bin/sh echo run only on an SGI machine echo type in linenumber read j echo value read value awk -f rmspass2 level=$value $j'step1.mlf' When the script is... (5 Replies)
Discussion started by: AreaMan
5 Replies

2. Shell Programming and Scripting

Passing shell variables to awk program..

Hello, Can we pass shell variables like $PATH etc. to a awk program part for example, awk ' { fieldValue=$PATH .... }' file (1 Reply)
Discussion started by: Vishnu
1 Replies

3. Shell Programming and Scripting

Passing Variables to Awk

Hi I have a unix shell script with an awk statement. I would like to print some of the fields of an input file. However, I would like to print them dynamically, ie by passing the literal $1 $3 into the script to define the output. I have tried the following: variable1='$1' awk... (2 Replies)
Discussion started by: Bab00shka
2 Replies

4. Shell Programming and Scripting

Passing awk Variables

I am trying to pass the results from a variable gathered from awk, however when I echo the 'PARSE' and 'SUB', the response is blank. This is my command. awk -F= '/Unit/''{ PARSE=substr($2,1,5) ; SUB=substr($2,1,1) }' inputfile.lst Is this a kind of valid attempt or am I obligated to declare... (3 Replies)
Discussion started by: gozer13
3 Replies

5. UNIX for Dummies Questions & Answers

Passing Shell Variables to an awk command

Hello, I have two files File1 & File2. File1 76 135 136 200 250 345 .... File2 1 24 1 35 1 36 1 72 .... I want to get all the values form File2 corresponding to the range in File 1 and feed it to a program. Is the code below right? Can I pass shell variables to awk in this... (2 Replies)
Discussion started by: Gussifinknottle
2 Replies

6. Shell Programming and Scripting

ksh passing to awk multiple dyanamic variables awk -v

Using ksh to call a function which has awk script embedded. It parses a long two element list file, filled with text numbers (I want column 2, beginning no sooner than line 45, that's the only known thing) . It's unknown where to start or end the data collection, dynamic variables will be used. ... (1 Reply)
Discussion started by: highnthemnts
1 Replies

7. Shell Programming and Scripting

Passing variables into AWK

I'm trying to use awk to write new entries to a hosts file if they don't exist. I need to do so depending on the type of system I have. Below is what I have, but it isn't working. awk -v myip1=$IP1 myip2=$IP2 myhost1=$HOST1 myhost2=$HOST2' BEGIN { mqhost1=0; mqhost2=0; stap1=0; stap2=0; } ... (4 Replies)
Discussion started by: Boomn4x4
4 Replies

8. UNIX for Dummies Questions & Answers

Passing Global Shell variables to awk

Hi All, Iam trying to pass global shell variables and is not working Main script is like below CYEAR=`date +"%y"` CFYEAR=`date +"%Y"` CMONTH=`date +"%m"` if then PMONTH=12 PYEAR=`expr $CYEAR - 1` PFYEAR=`expr $CFYEAR - 1` else PMONTH=`expr... (6 Replies)
Discussion started by: baanprog
6 Replies

9. Shell Programming and Scripting

Passing awk variables to bash variables

Trying to do so echo "111:222:333" |awk -F: '{system("export TESTO=" $2)}'But it doesn't work (2 Replies)
Discussion started by: urello
2 Replies

10. Shell Programming and Scripting

Awk: passing shell variables through and extracting text

Hello, new to the forums and to awk. Glad to be here. :o I want to pass two shell (#!/bin/sh) variables through to awk and use them. They will determine where to start and stop text extraction. The code with the variables hard-coded in awk works fine; the same code, but with the shell... (7 Replies)
Discussion started by: bedtime
7 Replies
mrd(1)							      General Commands Manual							    mrd(1)

NAME
mrd - mtools utility to remove a DOS directory SYNOPSIS
mrd msdosdirectory [msdosdirectories...] DESCRIPTION
The mrd command removes a directory from a DOS file system. If the directory is not empty, an error occurs. Unlike DOS conventions, this command allows multiple arguments. DOS subdirectory names that contain the '/' or '' separator are supported. If you use the '' separator or wildcards, you must enclose file names in quotes to protect them from the shell. The mcd command can be used to establish the device and the current working directory (relative to DOS), otherwise the default is A:. EXIT STATUS
The following exit values are returned: Success. Failure. ENVIRONMENT VARIABLES
The following environment variables affect the execution of mrd: If set, this variable names the file that contains the name of the current mtools working directory as established by the mcd command. If this variable is not set, the file $HOME/.mcwd is used. FILES
Contains the name of the current mtools working directory as established by the mcd command. If this file does not exist, the default mtools working directory is A:. Executable file SEE ALSO
Commands: mcd(1), mmd(1), mtools(1) mrd(1)
All times are GMT -4. The time now is 05:59 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy