Dear all,
Please advise what approach can remove all line break from a text file?
e.g.
Source file:
A
B
C
Target file:
A, B, C
Thanks,
Rock (5 Replies)
hi All,
Have a doubt in ksh..Am not familiar with arrays but i have tried out a script..
plzzzzz correct me with the script
My i/p File is:
(DESCRIPTION =
(ADDRESS_LIST =
(ADDRESS =
(PROTOCOL = TCP)
(Host = 192.168.2.2)
(Port = 1525)
)
)
(CONNECT_DATA = (SID = TESTDB1)
)
)
... (7 Replies)
Hi Experts,
My requirement is to read the csv file and need to remove if any line break in it.
sample data:
Row1: "Oslo, Symra kino",Oslo,130-7,Symra 1,130-7-91
Row2:"Tønsberg, Brygga Kino SF",Tønsberg,202-1,
Tønsberg SF 4,202-1-4
Expected data:
Row1: "Oslo, Symra... (6 Replies)
My requirement is to read the csv file and need to remove if any line break in it.
sample data:
Row1: "Oslo, Symra kino",Oslo,130-7,Symra 1,130-7-91Row2:"Tønsberg, Brygga Kino SF",Tønsberg,202-1.Tønsberg SF 4,202-1-4
Expected data:
Row1: "Oslo, Symra kino",Oslo,130-7,Symra... (4 Replies)
Hi,
we are trying to process a csv file,in which we are getting data with line breaks.How to remove the line break character in the file?
when i try to print the line break charcter using od -c,it gives as '\n' character for both line break and line feed.
Please provide your valuable... (6 Replies)
...when the lines use both a colon and commas to separate the parts you want read as information.
The first version of this script used cut and other non-Bash-builtins, frequently, which made it nice and zippy with little more than average processor load in GNOME Terminal but, predictably, slow... (2 Replies)
I cannot seem to get this to work..
I have a file which has about 100 lines, and there is no end of line (line break \n) at the end of each line, and this is causing problem when i paste them into an application.
the file looks like this
this is a test
that is a test
balblblablblhblbha... (1 Reply)
So I'm in a Unix class and our assignment was to go into VI and write a script to make this file tree. At the end of it, I'd like it to echo "This is the file tree you've created" then a line break, then . But I'm not sure as to who to do it. Is there a way for when I run it (./filesystem), the... (4 Replies)
Hello everyone!
I'm trying to make the below file1 look like file2, can anyone help?
Basically I just hit backspace on every line that starts with a number.
Thanks!
file1:
THIS#IS-IT1
4
THIS#IS-IT2
3
THIS#IS-IT3
2
THIS#IS-IT4
1
Result > file2: (4 Replies)
Hi,
I need to remove line breaks from a file, but only the ones at specific position.
Input file:
this is ok
this line is divided at posit
ion 30. The same as this one,
also position 30
the rest of lines are ok
with different lengths
The longest ones are always s
plitted at same... (15 Replies)
Discussion started by: qranumo
15 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)