Sponsored Content
Top Forums Shell Programming and Scripting How to show first 0 using seq or +1 count? Post 302602863 by Scrutinizer on Tuesday 28th of February 2012 02:17:17 PM
Old 02-28-2012
Quickly flung together :
Code:
for i in $(seq 0 $(date +"%H")); do printf "%s %02d:\n" "$(date +"%b %d")" "$i"; done | grep -f- "$LOGFILE" | grep -i alarm_type1 | wc-l


Last edited by Scrutinizer; 02-29-2012 at 03:09 AM..
This User Gave Thanks to Scrutinizer For This Post:
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

script to loop and check jumping seq.

Hi, Normally, I will manually to use "ll" command to list the following file from \FILE\CACHE\ directory and check the jump seq. Can I write a script to loop or/and check jump seq file (if jumped seq and show "missing seq no" message for me) -rw-rw----+ 1 user develop 14012 Sep 4... (1 Reply)
Discussion started by: happyv
1 Replies

2. Shell Programming and Scripting

declaring variable with for $(seq)

Hi guys. i have the following script: 1 #!/bin/bash 2 linkcount=$(grep "/portal" tickets | wc -l) 3 grep "/portal" tickets > links 4 for i in $(seq 1 $linkcount); do 5 echo "BLYAT" 6 let link$i=$(sed -n "$i"p links) 7 echo $ 8 done the problem is, that "let" can`t... (1 Reply)
Discussion started by: neverhood
1 Replies

3. Shell Programming and Scripting

Using Seq As A Variable With Padded Digits

Hi all. Im trying to use a sequence in a while loop like this below. I need it for navigating a year, month, day folder structure where a user can input the start date and have it go to the desired end date. The script will grab a certain file on each day then move onto the next. Ive got all that... (3 Replies)
Discussion started by: Grizzly
3 Replies

4. Shell Programming and Scripting

Using seq (Or alternative)

I usually just browse the forum/google for answers, however I've been stuck on a problem for a number of hours now and I've decided to join up and actually ask I've searched the forum ad naseum in an attempt to find answer to my query, however so far I have been unsuccessful. I'm no expert... (3 Replies)
Discussion started by: gtc
3 Replies

5. UNIX for Dummies Questions & Answers

Help with seq (print a series of dates)

Assuming one does not have such luxuries as bash, zsh, jot, rs, perl, etc. what is the most elegant way to print out a formatted date series like this: 01-01-2010 01-02-2010 01-03-2010 ... 02-01-2010 02-02-2010 ... Can I accomplish this with just basic shell builtins and seq, or... (3 Replies)
Discussion started by: uiop44
3 Replies

6. Shell Programming and Scripting

compare 2 files and show count same content.

$ cat File1 Non HTTP response code:java.net.ConnectException225073X 000000005143329Load time: 402335410224 Non HTTP response code: ava.net.ConnectException206423X 000000005143330Load time: 402305687161 Non HTTP response code: ava.net.ConnectException290212X 000000005143331Load time:... (1 Reply)
Discussion started by: ooilinlove
1 Replies

7. Shell Programming and Scripting

Using backspace in echo to show process count

i have something like this tablesName="abc def hij akn ... etc etc" count=0 for i in $tablesName do echo -en "\b\b\b\b\b\b\b\b\b\b\b\b\bTableCount: $count" count=`expr $count + 1` done the above is just a description wha i need is when the loop executes the... (1 Reply)
Discussion started by: vivek d r
1 Replies

8. UNIX for Dummies Questions & Answers

RNA-seq analysis

I am processing RNA-seq data files that have been aligned using RUM. One of the output files is a *.sam that includes: Unique alignments Non-unique alignments original read files I want to extract only the unique alignments by pulling out alignments that have "IH:i:1" (indicates this read... (2 Replies)
Discussion started by: genGirl23
2 Replies

9. Shell Programming and Scripting

awk command to find seq lines

I have a below file FILE.cfg JAN_01 VAR1=4 VAR2=SUM VAR3=PRIVATE JAN_10 VAR1=44 VAR2=GUN VAR3=NATUR JAN_20 VAR1=3 VAR2=TQN VAR3=COMMA code: (JAN_10 is argument passed from script) (6 Replies)
Discussion started by: Roozo
6 Replies

10. Shell Programming and Scripting

Easy seq Question

Hi! I'm trying to do this: 1 - 2 - 3 - 4 - 5 - I'm using seq for this: seq 1 20 > filename.txt How do I get the "-"? I've tried -f per man but can't get anything to work. Also, is there an easier or better way than using sequence? Thanks! (6 Replies)
Discussion started by: TonyBe
6 Replies
grep-changelog(1)					      General Commands Manual						 grep-changelog(1)

NAME
grep-changelog - print ChangeLog entries matching criteria SYNOPSIS
grep-changelog [options] [CHANGELOG...] DESCRIPTION
grep-changelog searches the named CHANGELOGs (by default files matching the regular expressions ChangeLog and ChangeLog.[0-9]+) for entries matching the specified criteria. At least one option or file must be specified. This program is distributed with GNU Emacs. OPTIONS
The program accepts unambiguous abbreviations for option names. --author=AUTHOR Print entries whose author matches regular expression AUTHOR. --text=TEXT Print entries whose text matches regular expression TEXT. --exclude=TEXT Exclude entries matching regular expression TEXT. --from-date=YYYY-MM-DD Only consider entries made on or after the given date. ChangeLog date entries not in the "YYYY-MM-DD" format are never matched. --to-date=YYYY-MM-DD Only consider entries made on or before the given date. --rcs-log Print output in a format suitable for RCS log entries. This format removes author lines, leading spaces, and file names. --with-date In RCS log format, print short dates. --reverse Show matches in reverse order. --version Display version information. --help Display basic usage information. COPYING
Copyright (C) 2008, 2009 Free Software Foundation, Inc. Permission is granted to make and distribute verbatim copies of this document provided the copyright notice and this permission notice are preserved on all copies. Permission is granted to copy and distribute modified versions of this document under the conditions for verbatim copying, provided that the entire resulting derived work is distributed under the terms of a permission notice identical to this one. Permission is granted to copy and distribute translations of this document into another language, under the above conditions for modified versions, except that this permission notice may be stated in a translation approved by the Free Software Foundation. grep-changelog(1)
All times are GMT -4. The time now is 01:33 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy